(-4)x3x(-125)x25x(-8)
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(-4\right)\left(-3\right)\left(-125\right).25.\left(-8\right)=\left[25\left(-4\right)\right]\left[\left(-125\right)\left(-8\right)\right]\left(-3\right)\)
\(=\left(-100\right).1000.\left(-3\right)=300.1000=300000\)
b) \(\left(-4\right).9\left(-125\right).25.\left(-8\right)=\left[25\left(-4\right)\right]\left[\left(-125\right)\left(-8\right)\right].9\)
\(=\left(-100\right).1000.9=\left(-100\right).9000=-900000\)
c) \(7.\left(-25\right)\left(-3\right).2.\left(-4\right)=\left[\left(-25\right)\left(-4\right)\left(-3\right)\right].7.2=-4200\)
d) \(\left[93-\left(20-7\right)\right]\div16=\left(93-13\right)\div16=80\div16=5\)
e) \(53-\left(-51\right)+\left(-53\right)+49=\left(53-53\right)+\left(51+49\right)=100\)
f) \(168-49+\left(-68\right)+4=168-49-68+4=55\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(29.\left(-13\right)-27.\left(-29\right)-14.\left(-29\right)\)
\(=13\left(-29\right)-27.\left(-29\right)-14.\left(-29\right)\)
\(=-29.\left(13-27-14\right)\)
\(=\left(-28\right).\left(-29\right)\)
\(=812\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1 d)
\(1-2+3-4+5-6+...+2013\)
\(=1+\left(-2+3\right)+\left(-4+5\right)+...+\left(-2012+2013\right)\)
\(=1+1+1+...+1\left(1006s\right)\)
\(=1006.1=1006\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án B
Ta có lim x → 0 f x = 2 1 + x - 8 - x 3 x = lim x → 0 2 1 + x - 8 - x 3 x
lim x → 0 2 x 1 + x + 1 - x 4 + 2 8 - x 3 + 8 - x 2 3 x = lim x → 0 2 1 + x + 1 + 1 4 + 2 8 - x 3 + 8 - x 2 3 = 13 12 .
![](https://rs.olm.vn/images/avt/0.png?1311)
= [(-125).(-8)].[(-4).25].3
= 1000. (-100).3
= (-100000).3
= -300000
-300000tickticktick nha!!!