(x+1) mũ 3=-64
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(4^{2x+4}=4^3\)
\(\Rightarrow\)\(2x+4=3\)
\(\Rightarrow\)\(x=\frac{-1}{2}\)
Ta có: \(3^{x-1}+3^{x-2}=108\)
\(\Rightarrow\)\(3^{x-1}+3^{x-2}=2^2.3^3\)
\(\Rightarrow\)\(3^{x-2}=3^3\)
\(\Rightarrow\)\(x-2=3\)
\(\Rightarrow x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>2x^3=58-4=54
=>x^3=27
=>x=3
b; =>(5-x)^5=2^5
=>5-x=2
=>x=3
c: =>(5x-6)^3=4^3
=>5x-6=4
=>5x=10
=>x=2
d: (3x)^3=(2x+1)^3
=>3x=2x+1
=>x=1
1=>2x3=54
=>x3=27 =>x=3
2=>(5-x)5=25
=>5-x=2
=>x=3
3=>(5x-6)3=43
=>5x-6=4
=>5x=10=>x=2
4=>3x=2x+1
=>x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(m,x^3+48x=12x^2+64\)
\(x^3+48x-12x^2-64=0\)
\(\left(x-4\right)^3=0\)
\(x=4\)
\(n,x^3-3x^2+3x=1\)
\(x^3-3x^2+3x-1=0\)
\(\left(x-1\right)^3=0\)
\(x=1\)
\(\Leftrightarrow x^3+48x-12x^2-64=0\)0
\(\Leftrightarrow\left(x-4\right)\left(x^2+4x+16\right)-12x\left(x-4\right)=0\)
\(\Leftrightarrow\left(x-4\right)\left(x^2-8x+16\right)=0\)
\(\Leftrightarrow\left(x-4\right)\left(x-4\right)^2=0\)
\(\Leftrightarrow\left(x-4\right)^3=0\)
\(\Leftrightarrow x-4=0\)
\(\Leftrightarrow x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(x - 5)2 = 16
=> (x - 5)2 = 42
=> \(\orbr{\begin{cases}x-5=4\\x-5=-4\end{cases}}\)
=> \(\orbr{\begin{cases}x=9\\x=1\end{cases}}\)
(2x - 1)3 = -64
=> (2x - 1)3 = -43
=> 2x - 1 = -4
=> 2x = -4 + 1
=> 2x = -3
=> x = -3/2
( x - 5)2 = 16
=> (x - 5)2 = 42
=> \(\orbr{\begin{cases}x-5=4\\x-5=-4\end{cases}}\)
=> \(\orbr{\begin{cases}x=9\\x=1\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(3^2.x+2^3.x=51\)
\(\Leftrightarrow x\left(3^2+2^3\right)=51\)
\(\Leftrightarrow17x=51\)
\(\Leftrightarrow x=3\)
Vậy
b) \(6^2.2-\left(84-3^2.x\right):7=69\)
\(\Leftrightarrow\left(84-3^2.x\right):7=3\)
\(\Leftrightarrow84-3^2.x=21\)
\(\Leftrightarrow3^2.x=63\)
\(\Leftrightarrow x=7\)
Vậy
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(3^x-2=2^7\)
\(\Leftrightarrow3^x=128+2=130\)(vô lý)
b: \(4^{x+1}=64\)
=>x+1=3
hay x=2
c: \(\left(5x+1\right)^2=1^{2016}=1\)
=>5x+1=1 hoặc 5x+1=-1
=>x=0 hoặc x=-2/5
d: \(2^{2\left(x-1\right)}=8\)
=>2(x-1)=3
=>x-1=3/2
hay x=5/2
![](https://rs.olm.vn/images/avt/0.png?1311)
a, (\(\frac{1}{2}\))x = \(\frac{1}{64}\)
<=> (\(\frac{1}{2}\))x = (\(\frac{1}{2}\))6
<=> x = 6
b, 35 :3x = 9
<=> 35 :3x = 32
<=> 3x = 35 :32
<=> 3x = 33
<=> x = 3
Chúc bạn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
a. x mũ 2 - 2x + 1 = 25
= x^2 + 2.x.1 + 1^2
= ( x + 1 ) ^2
ko bt có đúng ko nữa, mấy câu kia tui ko bt lm
( x + 1 )3 = -64
( x + 1 )3 = ( -4 )3
\(\Rightarrow\)x + 1 = -4
\(\Rightarrow\)x = ( -4 ) - 1
\(\Rightarrow\)x = -5.
Vậy x = -5.
#Y/n
(x+1)3 = (-4)3
x+1=3
x=3
k cho anh, em nha