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A, 7[x + 5] - 20 = 190
7x + 35 - 20 = 190
7x + 15 = 190
7x = 175
x = 25
B, 155 - 10[x + 1] = 55
155 - 10x - 10 = 55
-10x + 90 = 55
-10x = -35
x = 3.5
C, 6[x + 2^3] + 40 = 100
6[x + 8] + 40 = 100
6x + 48 + 40 = 100
6x + 88 = 100
6x = 1
2 x = 2
D, 15x - 133 = 17
15x = 150
x = 10
E, 90[x + 2] = 45
90x + 180 = 45
90x = -135
x = -1.5
F, 4x + 54 = 82
4x = 28
x = 7
G, 17x - 20 = 14
17x = 34
x = 2
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a) ta có: 4(x+32)-5=55 nên 4(x+32)=60, nên x+32=60/4=15
Mà 32=9 nên x=4
b) ta có 7(x+52)=210 nên x+52=30 . x+25=30 nên x=5
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 22 ( x + 32 ) - 5 = 55
=>4(x+9)-5=55
=>4(x+9)=60
=>x+9=15
=>x=6
b)7 ( x + 52 ) - 20 = 190
=>7(x+25)=210
=>x+25=30
=>x=5
c)6 ( x + 23 ) + 40 = 100
=>6(x+8)+40=100
=>6(x+8)=60
=>x+8=10
=>x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
22( x + 9 ) - 5 = 55
22( x + 9 ) = 55 + 5 = 60
x + 9 = 60 : 4 = 15
x = 15 - 9 = 6
7( x + 52 ) - 20 = 190
7( x + 52 ) = 190 + 20 = 210
x + 52 = 210 : 7 = 30
x = 30 - 52
x = -22
![](https://rs.olm.vn/images/avt/0.png?1311)
Đề:......
<=> 7. (x + 25) = 210
<=> x + 25 = 210 : 7
<=> x + 25 = 30
<=> x = 5
Vậy x = 5
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,2^{x+1}=3^y=12^x\Rightarrow2^{x+1}.3^y=2^{2x}.3y\)
\(\Rightarrow\frac{2^x}{2^{x+1}}=\frac{3^y}{3^x}\Rightarrow2^{2-x-x-1}=3^{y-x}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(7\left(x+5^2\right)-20=190\)
\(7\left(x+25\right)=190+20\)
\(7\left(x+25\right)=210\)
\(x+25=210:7\)
\(x+25=30\)
\(x=30-25\)
\(x=5\)
Vậy \(x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
7(x+5^2)-20=190
7(x+25)-20=190
7(x+25) =190+20
7(x+25) =210
x+25 =210/7
x+25 =30
x =30-5
x =5
Vậy x=5
\(7\left(x+5^2\right)-20=190\)
\(7\left(x+25\right)=190+20\)
\(7\left(x+25\right)=210\)
\(x+25=210:7\)
\(x+25=30\)
\(x=30-25\)
\(x=5\)
Vậy x=5
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 72-(4.x+15)=45 con cau b khong lam dc
4.x+15=72-45
4.x+15=27
4.x=27-15
4.x=8
x=8:4
x=2