Tính 25/5: 5/24 5/9×4/6 jup mik vs mn ơi
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\(\frac{5}{6}\cdot x+\frac{2}{3}\cdot\left(\frac{3}{5}\cdot x-\frac{6}{5}\right)=\frac{2}{9}-\frac{1}{2}\)
\(\Rightarrow\frac{5}{6}\cdot x+\frac{2}{3}\cdot\frac{3}{5}\cdot x-\frac{2}{3}\cdot\frac{6}{5}=-\frac{5}{18}\)
\(\Rightarrow\frac{5}{6}\cdot x+\frac{2}{5}\cdot x-\frac{4}{5}=-\frac{5}{18}\)
\(\Rightarrow x\cdot\left(\frac{5}{6}+\frac{2}{5}\right)=-\frac{5}{18}+\frac{4}{5}\)
\(\Rightarrow x\cdot\frac{37}{30}=\frac{47}{90}\)
\(\Rightarrow x=\frac{47}{90}\div\frac{37}{30}\)
\(\Rightarrow x=\frac{47}{111}\)
Vậy \(x=\frac{47}{111}\)
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1)1/6 - - 5/6 = 1/6 + 5/6 = 1
2)6/13 - -14/39 = 6/13 + 14/39= 32/39
3)4/5 - 4/-18 = 4/5 + 4/18= 46/45
4)7/21 - 9/-36 = 7/21 + 9/36 = 7/12
5)-12/18 - -21/35 = -12/18 + 21/35 = -1/15
6)-3/21 - 6/42 = -2/7
7)-18/24 - 15/21 = -41/28
8)1/6 - 2/5 =-7/30
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\(P=4^{25}\cdot\left(\dfrac{1}{2}-\dfrac{1}{3}\right)\cdot\left(\dfrac{1}{2}-\dfrac{1}{5}\right)\cdot\left(\dfrac{1}{2}-\dfrac{1}{7}\right)\cdot...\cdot\left(\dfrac{1}{2}-\dfrac{1}{101}\right)\)
\(P=4^{25}\cdot\left(\dfrac{1}{2}\cdot\left(\dfrac{1}{3}+\dfrac{1}{5}+\dfrac{1}{7}-...+\dfrac{1}{101}\right)\right)\)
\(P=4^{25}\cdot\left(\dfrac{1}{2}\cdot\left(\dfrac{1}{101}-\dfrac{1}{3}\right)\div2+1\right)\)
\(P=4^{25}\cdot\left(\dfrac{1}{2}\cdot\dfrac{1}{50}\right)\)
\(P=4^{25}\cdot\dfrac{1}{100}\)
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a: Xét tứ giác ABNM có
AM//BN
AM=BN
Do đó: ABNM là hình bình hành
mà \(\widehat{MAB}=90^0\)
nên ABNM là hình chữ nhật
a) \(\frac{25}{5}\div\frac{5}{24}=5\div\frac{5}{24}=24\)
b) \(\frac{5}{9}\times\frac{4}{6}=\frac{5}{9}\times\frac{2}{3}=\frac{10}{27}\)
25/5:5/24=600/25=24
5/9X4/6=20/54=10/27