giúp mình với 1-1/9-1/9=???
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![](https://rs.olm.vn/images/avt/0.png?1311)
Sửa đề: \(\dfrac{1}{1.9}\rightarrow\dfrac{9}{9.19}\)
Giải:
\(N=\dfrac{9}{9.19}+\dfrac{9}{19.29}+\dfrac{9}{29.39}+...+\dfrac{9}{2019.2029}\)
\(N=\dfrac{9}{10}.\left(\dfrac{10}{9.19}+\dfrac{10}{19.29}+\dfrac{10}{29.39}+...+\dfrac{10}{2019.2029}\right)\)
\(N=\dfrac{9}{10}.\left(\dfrac{1}{9}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{29}+\dfrac{1}{29}-\dfrac{1}{39}+...+\dfrac{1}{2019}-\dfrac{1}{2029}\right)\)
\(N=\dfrac{9}{10}.\left(\dfrac{1}{9}-\dfrac{1}{2029}\right)\)
\(N=\dfrac{9}{10}.\dfrac{2020}{18261}\)
\(N=\dfrac{202}{2029}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
\(9B=\frac{9^{2019}+9}{9^{2019}+1}=1+\frac{8}{9^{2019}+1}> 1+\frac{8}{9^{2020}+1}=\frac{9^{2020}+9}{9^{2020}+1}=9A\)
$\Rightarrow B>A$
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>2x-1/3=2
=>2x=7/3
=>x=7/6
b: Sửa đề: 1/11-5/22
\(\dfrac{8}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)
\(=\dfrac{8}{9}:\dfrac{-3}{22}+\dfrac{5}{9}:\dfrac{-9}{15}\)
\(=\dfrac{8}{9}\cdot\dfrac{-22}{3}+\dfrac{5}{9}\cdot\dfrac{-5}{3}\)
\(=\dfrac{-66-25}{27}=\dfrac{-91}{27}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1 / 9 + 2 / 9 + 4 / 9 = 7 / 9
5 / 5 + 6 / 5 + 1 = 15 / 5 = 3
12 / 2 + 4 / 2 + 1 + 3 / 2 = 21 / 2
7 / 3 + 6 / 3 + 1 + 1 = 19 / 3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2}{9}\div\frac{2}{9}\times\frac{1}{2}\)
\(=\frac{2}{9}\times\frac{9}{2}\times\frac{1}{2}\)
\(=\frac{2\times9\times1}{9\times2\times2}\)
\(=\frac{1}{2}\)
TL
\(\frac{2}{9}:\frac{2}{9}x\frac{1}{2}\)
=1X\(\frac{1}{2}\)
=\(\frac{1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
S=1+9+92+93+...+92017
9S =(90+9+92+93+...+92017).2
9S =9+92+93+94+...+92017+92018
9S-S =(9+92+93+94+...+92017+92018)-(90+9+92+93+...+92017)
8S =92018-90
S =(92018-90):8
![](https://rs.olm.vn/images/avt/0.png?1311)
1+1-2-2-3-4-5-6-7-8-9+1+3+5+7+9+10
=-44+1+3+5+7+9+10
=-44+35
=-9
![](https://rs.olm.vn/images/avt/0.png?1311)
1-\(\frac{1}{9}\)- \(\frac{1}{9}\)=\(\frac{7}{9}\)
là sao,