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=>-3/5-3/8x-2/3=-5/48+15/32x

=>-27/32x=93/80

hay x=-62/45

a: =>9x^2+6x+1-6(2x^2-13x+21)=0

=>9x^2+6x+1-12x^2+78x-126=0

=>-3x^2+84x-125=0

=>\(x\in\left\{26.42;1.58\right\}\)

b: =>(3x+1)[(2x-5)^2-(x-3)^2]=0

=>(3x+1)(2x-5-x+3)(2x-5+x-3)=0

=>(3x+1)(x-2)(3x-8)=0

=>\(x\in\left\{-\dfrac{1}{3};2;\dfrac{8}{3}\right\}\)

c; =>(x+5)(0,75x-3+1,25x)=0

=>(x+5)(2x-3)=0

=>x=3/2 hoặc x=-5

11 tháng 9 2018

\(-\dfrac{6}{11}\cdot\left[\left(0.375x+\dfrac{4}{5}\right)-\left(-\dfrac{5}{4}-7\right)\cdot2\right]=0\)

\(\left[\left(0.375x+\dfrac{4}{5}\right)-\left(-\dfrac{5}{4}-7\right)\cdot2\right]=0\)

\(\left[\left(\dfrac{3}{8}x+\dfrac{4}{5}\right)-\dfrac{-33}{4}\cdot2\right]=0\)

\(\left[\left(\dfrac{3}{8}x+\dfrac{4}{5}\right)-\dfrac{-33}{2}\right]=0\)

Từ đây bn lm tiếp nhé☺

29 tháng 10 2021

3: \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)

\(\Leftrightarrow\left|x-\dfrac{3}{4}\right|=\dfrac{1}{2}\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{2}\\x-\dfrac{3}{4}=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{1}{4}\end{matrix}\right.\)

a:=>0,75x-x+1,25x=0,2

=>x=0,2

b: =>1/3-x=-3/6+4/6=1/6

=>x=1/3-1/6=1/6

c: =>(x-1)/45=-6/30=-1/5

=>x-1=-9

=>x=-8

d: =>(2/5x-1)=-5/7

=>2/5x=2/7

=>x=5/7

16 tháng 9 2018

\(\left(-0,75x+\frac{5}{2}\right).\frac{7}{4}-\left(\frac{-1}{3}\right)=\frac{-5}{7}\)

\(\left(-0,75x+\frac{5}{2}\right).\frac{7}{4}=\frac{-5}{7}+\left(\frac{-1}{3}\right)\)

\(\left(-0,75x+\frac{5}{2}\right).\frac{7}{4}=\frac{-22}{21}\)

\(-0,75x+\frac{5}{2}=\frac{-22}{21}:\frac{7}{4}\)

\(-0,75x+\frac{5}{2}=\frac{-88}{147}\)

\(-0,75x=\frac{-88}{147}-\frac{5}{2}\)

\(-0,75x=\frac{-911}{294}\)

\(x=\frac{-911}{294}:\left(-0,75\right)\)

\(x=\frac{1822}{441}\)