-3/5-(0,375x+2/3)=-0,625*(1/6-0,75x)
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a: =>9x^2+6x+1-6(2x^2-13x+21)=0
=>9x^2+6x+1-12x^2+78x-126=0
=>-3x^2+84x-125=0
=>\(x\in\left\{26.42;1.58\right\}\)
b: =>(3x+1)[(2x-5)^2-(x-3)^2]=0
=>(3x+1)(2x-5-x+3)(2x-5+x-3)=0
=>(3x+1)(x-2)(3x-8)=0
=>\(x\in\left\{-\dfrac{1}{3};2;\dfrac{8}{3}\right\}\)
c; =>(x+5)(0,75x-3+1,25x)=0
=>(x+5)(2x-3)=0
=>x=3/2 hoặc x=-5
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\(-\dfrac{6}{11}\cdot\left[\left(0.375x+\dfrac{4}{5}\right)-\left(-\dfrac{5}{4}-7\right)\cdot2\right]=0\)
⇒ \(\left[\left(0.375x+\dfrac{4}{5}\right)-\left(-\dfrac{5}{4}-7\right)\cdot2\right]=0\)
⇒ \(\left[\left(\dfrac{3}{8}x+\dfrac{4}{5}\right)-\dfrac{-33}{4}\cdot2\right]=0\)
⇒ \(\left[\left(\dfrac{3}{8}x+\dfrac{4}{5}\right)-\dfrac{-33}{2}\right]=0\)
Từ đây bn lm tiếp nhé☺
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3: \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)
\(\Leftrightarrow\left|x-\dfrac{3}{4}\right|=\dfrac{1}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{2}\\x-\dfrac{3}{4}=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{1}{4}\end{matrix}\right.\)
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a:=>0,75x-x+1,25x=0,2
=>x=0,2
b: =>1/3-x=-3/6+4/6=1/6
=>x=1/3-1/6=1/6
c: =>(x-1)/45=-6/30=-1/5
=>x-1=-9
=>x=-8
d: =>(2/5x-1)=-5/7
=>2/5x=2/7
=>x=5/7
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\(\left(-0,75x+\frac{5}{2}\right).\frac{7}{4}-\left(\frac{-1}{3}\right)=\frac{-5}{7}\)
\(\left(-0,75x+\frac{5}{2}\right).\frac{7}{4}=\frac{-5}{7}+\left(\frac{-1}{3}\right)\)
\(\left(-0,75x+\frac{5}{2}\right).\frac{7}{4}=\frac{-22}{21}\)
\(-0,75x+\frac{5}{2}=\frac{-22}{21}:\frac{7}{4}\)
\(-0,75x+\frac{5}{2}=\frac{-88}{147}\)
\(-0,75x=\frac{-88}{147}-\frac{5}{2}\)
\(-0,75x=\frac{-911}{294}\)
\(x=\frac{-911}{294}:\left(-0,75\right)\)
\(x=\frac{1822}{441}\)
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=>-3/5-3/8x-2/3=-5/48+15/32x
=>-27/32x=93/80
hay x=-62/45