giúp em ạ e cảm ơn
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1 weight
2 daily
3 endless
4 discussion
5 available
6 organizing
7 happier
8 attractive
9 ashamed
10 desicion
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1:
(SAB), (SBC) vuông góc (BAC)
=>SB vuông góc (ABC)
AC vuông góc AB,SB
=>AC vuông góc (SAB)
=>AC vuông góc BH
mà SA vuông góc BH
nên BH vuông góc (SAC)
=>BH vuông góc SC
mà SC vuông góc BK
nên SC vuông góc (BHK)
c: (SH;(BHK))=góc SHK=(SA;BHK)
BC=BA/cos60=2a
SC=căn SB^2+BC^2=ăcn 5
SB^2=SK*SC
=>SK=a*căn 5/5
SA=căn SB^2+AB^2=a*căn 2
SB^2=SH*SA
=>SH=a*căn 2/2
sin SHK=căn 10/5
=>góc SHK=39 độ
![](https://rs.olm.vn/images/avt/0.png?1311)
1 telling
2 to come
3 having
4 talking
5 to speak
6 giving
7 carry
8 to study
9 waiting
10 to start
11 to help
12 going
13 to bring
14to visit
15 going
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1 preparing
2 working - finishing
3 to give - smoking
4 talking - eating
5 arguing - working
6 to think - making
7 to come - standing
8 solving
9to lock - going
10 to persuade - change
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1 watching - reading
2 playing - doing
3 to go
4 Did you see
5 to dream - were
6 showing - to send
7 going
8 doing
9 reading
10 to seeing
#\(Vion.Serity\)
#\(yGLinh\)
1 telling
2 to come
3 having
4 talking
5 to speak
6 giving
7 carry
8 to study
9 waiting
10 to start
11 to help
12 going
13 to bring
14to visit
15 going
--------------------------------
1 preparing
2 working - finishing
3 to give - smoking
4 talking - eating
5 arguing - working
6 to think - making
7 to come - standing
8 solving
9to lock - going
10 to persuade - change
-------------------------------------
1 watching - reading
2 playing - doing
3 to go
4 Did you see
5 to dream - were
6 showing - to send
7 going
8 doing
9 reading
10 to seeing
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a: =>(x+5)(4-x)=0
=>x=4 hoặc x=-5
b: =>2x(2x-1)=0
=>x=0 hoặc x=1/2
c: =>2x(x^2+1)+x^2+1=0
=>(x^2+1)(2x+1)=0
=>2x+1=0
=>x=-1/2
d: Δ=(-3)^2-4*1*4=9-16=-7<0
=>PTVN
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 11:
b: -x^2+x-m<=0 với mọi x
Δ=1^2-4*(-1)*(-m)=1-4m
Để BPT luôn đúng thì 1-4m<=0 và -1<0
=>4m>=1
=>m>=1/4
c: mx^2+mx-1>=0
TH1: m=0
=>-1>=0(vô lý)
=>Nhận)
TH2: m<>0
Δ=m^2-4*m*(-1)=m^2+4m
Để BPT vô nghiệm thì m^2+4m<=0 và m<0
=>-4<=m<=0 và m<0
=>-4<=m<0
\(B=\left(\frac{x-2}{2x-2}-\frac{3}{2-2x}-\frac{x+3}{2x+2}\right):\left(1-\frac{x-3}{x+1}\right)\) \(ĐKXĐ:x\ne\pm1\)
\(B=\left(\frac{\left(x-2\right)\left(x+1\right)}{2\left(x-1\right)\left(x+1\right)}+\frac{3\left(x+1\right)}{2\left(x-1\right)\left(x+1\right)}-\frac{\left(x+3\right)\left(x-1\right)}{2\left(x-1\right)\left(x+1\right)}\right)\)\(:\left(\frac{x+1-x+3}{x+1}\right)\)
\(B=\left(\frac{x^2-x-2+3x+3-x^2-2x+3}{2\left(x-1\right)\left(x+1\right)}\right):\left(\frac{4}{x+1}\right)\)
\(B=\left(\frac{4}{2\left(x-1\right)\left(x+1\right)}\right):\left(\frac{4}{x+1}\right)\)
\(B=\frac{4}{2\left(x-1\right)\left(x+1\right)}.\frac{x+1}{4}=\frac{1}{2\left(x-1\right)}\)