5x-1 -13 = 612 giúp mình nhé !
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4abc-abc4=4000+abc-10*abc-4=(4000-4)-(10*abc-abc)=3996-9*abc=612. =>9*abc=3996-612. Bạn tự làm tiếp nhé.
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345 - 612 + 1655 - 388
= (345 + 1655) - (612 + 388)
= 2000 - 1000
= 1000
345 - 612 + 1655 - 388
= (345 + 1655) - (612 + 388)
= 2000 - 1000
= 1000
Chúc cậu học tốt☘✿
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\(1-\frac{5x}{2}=\frac{13}{36}-x+\frac{1}{3}\)
\(\Leftrightarrow\frac{2-5x}{2}=\frac{13}{36}-\frac{36x}{36}+\frac{12}{36}\)
\(\Leftrightarrow\frac{36-60x}{36}=\frac{13-36x+12}{36}\Leftrightarrow36-60x=13-36x+12\)
\(\Leftrightarrow11-24x=0\Leftrightarrow x=\frac{11}{24}\)
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ta có:
\(1+\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+...+\frac{1}{x\left(x+3\right)}\)=1\(\frac{7}{24}\)\(=\frac{31}{24}\)
\(1+\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{x\left(x+3\right)}=\frac{31}{24}\)
\(3+\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{x\left(x+3\right)}=\frac{31}{3}\)
\(3+1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{31}{3}\)
\(3+1-\frac{1}{x+3}=\frac{31}{3}\)
\(4-\frac{1}{x+3}=\frac{31}{3}\)
\(\frac{1}{x+3}=4-\frac{31}{3}=\frac{-19}{3}\)
=>ko tìm được x
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Ta có :
5x + 1 - ( 5x - x2 )
= 5x + 1 - 5x + x2
= x2 + 1
vì x2 \(\ge\)0 nên x2 + 1 > 0
Vậy đa thức trên không có nghiệm
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\(a,5x-114=386\\ \Leftrightarrow5x=500\\ \Leftrightarrow x=100\\ b,x\cdot\left(12\cdot4-2\cdot18\right)=612\\ \Leftrightarrow x\cdot\left(48-36\right)=612\\ \Leftrightarrow x\cdot12=612\\ \Leftrightarrow x=51\)
c, x : 27 = 23 dư 9
⇒ \(x=23\cdot27+9\\\Leftrightarrow x=630\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5^{x-1}-13=612\)
\(\Leftrightarrow5^{x-1}=625\)
\(\Leftrightarrow5^{x-1}=5^4\)
\(\Leftrightarrow x-1=4\)
\(\Leftrightarrow x=5\)
5x-1 -13 = 612
5x-1 =612+13
5x-1 =625
5x-1 =54
=>x-1=4
x=4+1
x=5