x/4 = -5/3
1/2 + x = 1,5 .4/3
2/3 - 1/3 .x =1/5
(x - 5,2).1/3=15
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28 tháng 2 2022
a: \(\dfrac{96}{\left(x-4\right)\left(x+4\right)}+\dfrac{7+x}{4-x}=\dfrac{2x-1}{x+4}-3\)
\(\Leftrightarrow\dfrac{96}{\left(x-4\right)\left(x+4\right)}-\dfrac{\left(x+7\right)\left(x+4\right)}{\left(x-4\right)\left(x+4\right)}=\dfrac{\left(2x-1\right)\left(x-4\right)}{\left(x+4\right)\left(x-4\right)}-\dfrac{3\left(x-4\right)\left(x+4\right)}{\left(x-4\right)\left(x+4\right)}\)
Suy ra: \(96-x^2-11x-28=2x^2-9x+4-3\left(x^2-16\right)\)
\(\Leftrightarrow-x^2-11x+68=2x^2-9x+4-3x^2+48\)
\(\Leftrightarrow-x^2-11x+68=-x^2-9x+52\)
=>-11x+68=-9x+52
=>-2x=-16
hay x=8(nhận)
b: \(\dfrac{2}{x-1}+\dfrac{3}{x-2}=\dfrac{3}{x-3}\)
\(\Leftrightarrow2\left(x-2\right)\left(x-3\right)+3\left(x-1\right)\left(x-3\right)=3\left(x-1\right)\left(x-2\right)\)
\(\Leftrightarrow2\left(x^2-5x+6\right)+3\left(x^2-4x+3\right)=3\left(x^2-3x+2\right)\)
\(\Leftrightarrow2x^2-10x+12+3x^2-12x+9=3x^2-9x+6\)
\(\Leftrightarrow5x^2-22x+21-3x^2+9x-6=0\)
\(\Leftrightarrow2x^2-13x+15=0\)
\(\Leftrightarrow2x^2-10x-3x+15=0\)
=>(x-5)(2x-3)=0
=>x=5(nhận) hoặc x=3/2(nhận)
23 tháng 1 2017
a) X + 1/4 = 5/8 + 2/5
X + 1/4 = 41/10
X = 41/10 - 1/4
X = 31/40
b) X : 3/4 = 4/10 - 4/10
X : 3/4 = 0
X = 0
c) X + 3,4 x 2,6 = 4,8 x 5,2
X + 8,84 = 24,96
X = 24,96 : 8,84
X = 48/17
d) X : 1,5 + 1,5 = 0,8N x 2
= bó tay nhé
3 tháng 2 2021
1/ 3-2x+4+6x=x+7+3x
⇔-2x+6x-x-3x=0
⇔0x=0 (Vô số nghiệm)
2/-6(1,5-2x)=3(-15+2x)
⇔-9+12x=-45+6x
⇔6x+36=0
⇔6(x+6)=0
⇔x+6=0
⇔x=-6
Vậy S ϵ {-6}
3/ 3(2x-5)+5(x-1)=4(x+1)
⇔6x-15+5x-5=4x+4
⇔7x=24
⇔x=\(\dfrac{24}{7}\)
Vậy S ϵ {\(\dfrac{24}{7}\)}
3 tháng 2 2021
1) Ta có: \(3-2x+4+6x=x+7+3x\)
\(\Leftrightarrow4x+7=4x+7\)
\(\Leftrightarrow4x+7-4x-7=0\)
\(\Leftrightarrow0x=0\)(luôn đúng)
Vậy: S={x|\(x\in R\)}
2) Ta có: \(-6\cdot\left(1.5-2x\right)=3\left(-15+2x\right)\)
\(\Leftrightarrow-9+12x=-45+6x\)
\(\Leftrightarrow12x-9+45-6x=0\)
\(\Leftrightarrow6x+36=0\)
\(\Leftrightarrow6x=-36\)
hay x=-6
Vậy: S={-6}
3) Ta có: \(3\left(2x-5\right)+5\left(x-1\right)=4\left(x+1\right)\)
\(\Leftrightarrow6x-15+5x-5=4x+4\)
\(\Leftrightarrow11x-20-4x-4=0\)
\(\Leftrightarrow7x-24=0\)
\(\Leftrightarrow7x=24\)
\(\Leftrightarrow x=\dfrac{24}{7}\)
Vậy: \(S=\left\{\dfrac{24}{7}\right\}\)
\(\dfrac{x}{4}=-\dfrac{5}{3}\)\(\Rightarrow x.3=-5.4\Rightarrow3x=-20\Rightarrow x=\dfrac{-20}{3}\)
\(\dfrac{1}{2}+x=1,5.\dfrac{4}{3}\)\(\Rightarrow\dfrac{1}{2}+x=2\Rightarrow x=2-\dfrac{1}{2}\Rightarrow x=\dfrac{3}{2}\)
\(\dfrac{2}{3}-\dfrac{1}{3}.x=\dfrac{1}{5}\Rightarrow\)\(\dfrac{1}{3}.x=\dfrac{2}{3}-\dfrac{1}{5}\Rightarrow\dfrac{1}{3}.x=\dfrac{7}{15}\Rightarrow x=\dfrac{7}{15}:\dfrac{1}{3}\)\(\Rightarrow x=\dfrac{7}{5}\)
\(\left(x-5,2\right).\dfrac{1}{3}=15\Rightarrow x-5,2=15:\dfrac{1}{3}\Rightarrow x-5,2=45\)\(\Rightarrow x=45+5,2\Rightarrow x=50,2\)
P/s Nhớ tick cho mình nha. Thanks bạn