a, 5x-3{ 4x-2[ 4x-3( 5x-2)]}= 182
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30 tháng 5 2022
Câu 1: \(x^2+5x=2\left(x+5\right)\)
\(\Leftrightarrow x\left(x+5\right)-2\left(x+5\right)=0\)
\(\Leftrightarrow\left(x+5\right)\left(x-2\right)=0\)
=>x=-5 hoặc x=2
Câu 2:
Ta có: \(5x^4y^6⋮4x^2y^n\)
=>6-n>=0
hay n<=6
ND
3 tháng 6 2018
1.
a) \(\left\{4x-2\left(x-3\right)-3\left[x-3\left(4-2x\right)+8\right]\right\}.\left(-3x\right)\)
= \(\left[4x-2x+6-3\left(x-12+6x\right)+8\right].\left(-3x\right)\)
\(=\left(4x-2x+6-3x+36-18x+8\right).\left(-3x\right)\)
= \(\left(-19x+50\right).\left(-3x\right)\)
\(=57x^2-150x\)
b) \(5\left(3x^2+4y^3\right)+\left[9\left(2x^2-y^3\right)-2\left(x^2-5y^3\right)\right]\)
\(=15x^2+20y^3+\left(18x^2-9y^3-2x^2+10y^3\right)\)
\(=15x^2+20y^3+16x^2+y^3\)
\(=31x^2+21y^3\)
2.
a) \(5x\left(1-2x\right)-3x\left(x+18\right)=0\)
\(\Rightarrow5x-10x^2-3x^2-54x=0\)
\(\Rightarrow-49x-13x^2=0\)
\(\Rightarrow x\left(-49-13x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{-49}{13}\end{matrix}\right.\)
b)
\(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(\Rightarrow5x-3\left[4x-2\left(4x-15x+6\right)\right]=182\)
\(\Rightarrow5x-3\left(4x-8x+30x-12\right)=182\)
\(\Rightarrow5x-12x+24x-90x+36=182\)
\(\Rightarrow-73x-146=0\)
\(\Rightarrow x=-2\)
13 tháng 9 2020
\(5x-\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(5x-\left[4x-2\left(4x-15x+6\right)\right]=182\)
\(5x-\left[4x-2\left(-11x+6\right)\right]=182\)
\(5x-\left(4x+22x-12\right)=182\)
\(5x-\left(26x-12\right)=182\)
\(5x-26x+12=182\)
\(-21x=182-12\)
\(-21x=170\)
\(x=-\frac{170}{21}\)
19 tháng 5 2022
\(\Leftrightarrow5x-3\left\{4x-2\left[4x-15x+6\right]\right\}=182\)
\(\Leftrightarrow5x-3\left\{4x-2\left(-11x+6\right)\right\}=182\)
\(\Leftrightarrow5x-3\left\{4x+22x-12\right\}=182\)
\(\Leftrightarrow5x-3\left(26x-12\right)=182\)
\(\Leftrightarrow5x-78x+36=182\)
=>-73x=146
hay x=-2
16 tháng 8 2020
a) \(=x^4-x^3-2x^3+2x^2+2x^2-2x-x+1\)
\(=x^3\left(x-1\right)-2x^2\left(x-1\right)+2x\left(x-1\right)-\left(x-1\right)\)
\(=\left(x^3-2x^2+2x-1\right)\left(x-1\right)\)
\(=\left(x^3-x^2-x^2+x+x-1\right)\left(x-1\right)\)
\(=\left(x^2-x+1\right)\left(x-1\right)^2\)
c)
\(=6x^4-12x^3+17x^3-34x^2-4x^2+8x-3x+6\)
\(=6x^3\left(x-2\right)+17x^2\left(x-2\right)-4x\left(x-2\right)-3\left(x-2\right)\)
\(=\left(6x^3+17x^2-4x-3\right)\left(x-2\right)\)
\(=\left(6x^3+18x^2-x^2-3x-x-3\right)\left(x-2\right)\)
\(=\left(6x^2-x-1\right)\left(x+3\right)\left(x-2\right)\)
\(=\left(2x-1\right)\left(3x+1\right)\left(x+3\right)\left(x-2\right)\)
16 tháng 8 2020
b)
\(=x^4+1011x^2+1011+\left(1010x^2-2020x+1010\right)\)
\(=x^4+1011x^2+1011+1010\left(x^2-2x+1\right)\)
\(=x^4+1011x^2+1011+1010\left(x-1\right)^2\)
CÓ: \(x^4+1010\left(x-1\right)^2+1011x^2\ge0\forall x\)
=> \(x^4+1010\left(x-1\right)^2+1011x^2+1011\ge1011>0\forall x\)
=> ĐA THỨC b > 0 => Ko ph được thành nhân tử.
9 tháng 6 2016
5x - 3{4x - 2[4x - 3(5x - 2)]} = 5x - 12x + 6[4x - 3(5x - 2)] = -7x + 24x - 18(5x - 2) = 17x - 90x + 36 = -73x + 36 = 182
=> -73x = 182 - 36 = 146 => x = 146 : (-73) = -2
2 tháng 6 2016
5x-3{4x-2[4x-3(5x-2)]}
= 5x - 3.[4x - 2(4x - 15x + 6)]
= 5x - 3.(4x - 8x + 30x - 12)
= 5x - 12x + 24x - 90x + 36
= -73x + 36 = 182
=> -73x = 182 - 36 = 146
=> x = 146 : (-73) = -2
2 tháng 6 2016
\(VT=-\left(73x-36\right)\)
\(\Leftrightarrow-\left(73x-36\right)=182\)
\(\Leftrightarrow36-73x=182\)
\(\Leftrightarrow-73x=182-36\)
\(\Leftrightarrow-73x=146\)
\(\Leftrightarrow x=-2\)
2 tháng 6 2016
Mình nghĩ là vậy :
5x -3 { 4x - 2 [ 4x - 3 (5x - 2)]} = 182
<=> 5x -3 { 4x -2 [ 4x - 15x +6 ]} =182
<=> 5x -3 { 4x -2 [ -11x +6 ]} =182
<=> 5x -3 { 4x + 22x -12 } = 182
<=> 5x -3 { 26x -12 } =182
<=> 5x - 78x + 36 = 182
<=> -73x = 146
<=> x= -2
TN
2 tháng 6 2016
\(VT=-\left(73x-36\right)\)
\(\Leftrightarrow-\left(73x-36\right)=182\)
\(\Leftrightarrow36-73x=182\)
\(\Leftrightarrow-73x=182-36\)
\(\Leftrightarrow-73x=146\)
\(\Leftrightarrow x=-2\)
\(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(\Rightarrow5x-3\left\{4x-2\left[4x-15x+6\right]\right\}=182\)
\(\Rightarrow5x-3\left\{4x-2\left[-11x+6\right]\right\}=182\)
\(\Rightarrow5x-3\left\{4x-\left(-22x+12\right)\right\}=182\)
\(\Rightarrow5x-3\left\{4x+22x-12\right\}=182\)
\(\Rightarrow5x-3\left\{26x-12\right\}=182\)
\(\Rightarrow5x-78x+36=182\)
\(\Rightarrow-73x=146\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)
\(5x-3.\left(4x-2.\left(4x-3.\left(5x-2\right)\right)\right)=182\\ \)
\(\Leftrightarrow5x-3.\left(4x-2.\left(4x-15x+6\right)\right)=182\)\(\Leftrightarrow5x-3.\left(4x-2.\left(6-11x\right)\right)=182\)
\(\Leftrightarrow5x-3.\left(4x-12+22x\right)=182\Leftrightarrow5x-3.\left(26x-12\right)=182\)
\(\Leftrightarrow5x-78x+36=182\Leftrightarrow-73x=146\Leftrightarrow x=-2\)