2001*2002+2003*1991+11+2002*7
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\(\dfrac{2001+2002}{2002+2003}< \dfrac{2001}{2002}+\dfrac{2002}{2003}\)
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2001 . 2022 + 1981+2003 . 21/ 2002 . 2003 - 2001. 2002
= ( 2001. 2002 - 2001 . 2022 ) + ( 1981 + 2003 . 21/ 2002 . 2003)
= 0+( 1981 + ( 2003 . 21 / 2002 + 1)
= 0 + 1981+( 2002 . 21/2002+1+1)
= 1981 + ( 21+2)
= 1981+ 23
= 2004
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a) \(1-2-3+4+5-6-7+...+2001-2002-2003+2004\)
\(=\left(1-2-3+4\right)+\left(5-6-7+8\right)+...+\left(2001-2002-2003+2004\right)\)
\(=0+0+...+0=0\)
b) \(1+2-3-4+5+6-7-8+...+2001+2002-2003-2004\)
\(=\left(1+2-3-4\right)+\left(5+6-7-8\right)+...+\left(2001+2002-2003-2004\right)\)
\(=\left(-4\right)+\left(-4\right)+...+\left(-4\right)\)
\(=\left(-4\right)\cdot501=\left(-2004\right)\)
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8008000
8008000