Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(2^{13}< 2^{16}\)
Mà \(7.2^{13}\)
\(\Rightarrow7.2^{13}>2^{16}\)
b) Ta có: \(199^{20}=\left(199^4\right)^5\)
\(2003^{15}=\left(2003^3\right)^5\)
Vì \(199^4< 2003^3\)
Vậy \(199^{20}< 2003^{15}\)
c) Ta có: \(3^{39}=\left(3^{13}\right)^3\)
\(11^{21}=\left(11^7\right)^3\)
Vì \(3^{14}< 11^7\)
Vậy \(3^{39}< 11^{21}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Ta có : \(119^{20}=\left(119^4\right)^5=200533921^5\)
\(2003^{15}=\left(2003^3\right)^5=8036054027^5\)
Vì \(200533921< 8036054027\)nên \(200533921^5< 8036054027^5\)
hay \(119^{20}< 2003^{15}\)
Vậy \(119^{20}< 2003^{15}\)
b, Ta có : \(3^{39}=\left(3^{13}\right)^3=1594323^3\)
\(11^{21}=\left(11^7\right)^3=19487171^3\)
Vì \(1594323< 19487171\)nên \(1594323^3< 19487171^3\)
hay \(3^{39}< 11^{21}\)
Vậy \(3^{39}< 11^{21}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ 19920 = ( 1994)5 = 15682392015
200315 = ( 20033 )5 = 80360540275
1568239201<8036054027\(\Rightarrow\)19920 < 200315
b/ 339 = ( 313 )3 = 15943233
1121 = ( 117 )3 = 194871713
1594323<19487171\(\Rightarrow\)339 < 1121
Hk tốt
a. Ta có : \(199^{20}< 200^{20}=\left(8.25\right)^{20}=2^{60}.5^{40}< 2^{60}.5^{45}=\left(16.125\right)^{15}=2000^{15}< 2003^{15}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)1714>1614=256>3211=222>3111
b)102330<102430=2300<2305=3261<3361
c)8217>8117=368>363=2721>2621
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: 2003^152>2003^20>199^20
Vậy 2003^152>199^20
b) Ta có: 3^39=(3^13)^3=1594323^3
11^21=(11^7)^3=19487171^3
Vì 1594323^3<19487171^3 nên 3^39<11^21
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(199^{20}=\left(199^4\right)^5\)
= \(2003^{15}=\left(2003^3\right)^5\)
Vậy \(\left(2003^3\right)^5>\)
b) /rightnarrow/
Khó quá!