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3\(\frac{1}{2}\)+4\(\frac{5}{7}\)- 5\(\frac{5}{14}\)=
=\(\frac{7}{2}\)+\(\frac{33}{7}\)-\(\frac{65}{14}\)
=\(\frac{49}{14}\)+\(\frac{66}{14}\)-\(\frac{65}{14}\)
=\(\frac{50}{14}\)
\(4\frac{2}{3}+3\frac{2}{7}=\frac{14}{3}+\frac{23}{7}=\frac{98+69}{21}=\frac{167}{21}\)
\(1\frac{3}{4}\times2\frac{5}{6}=\frac{7}{4}\times\frac{17}{6}=\frac{119}{24}\)
\(7\frac{3}{4}-2\frac{1}{8}=\frac{31}{4}-\frac{17}{8}=\frac{62-17}{8}=\frac{45}{8}\)
\(8\frac{5}{9}:5\frac{1}{2}=\frac{77}{9}:\frac{11}{2}=\frac{77}{9}\times\frac{2}{11}=\frac{154}{99}=\frac{14}{9}\)
+) = \(\frac{20}{7}\)
+) = \(\frac{101}{22}\)
tk mik nha
mik khỏi chép lại đề
+) = \(\frac{7}{2}+\frac{33}{7}-\frac{75}{14}\)
= \(\frac{49}{14}+\frac{66}{14}-\frac{75}{14}\)
= \(\frac{115}{14}-\frac{75}{14}\)
= \(\frac{20}{7}\)
+) = \(\frac{9}{2}+\frac{1}{2}:\frac{11}{2}\)
= \(\frac{9}{2}+\frac{1}{2}\)x \(\frac{2}{11}\)
= \(\frac{9}{2}+\frac{1}{11}\)
= \(\frac{99}{22}+\frac{2}{22}\)
= \(\frac{101}{22}\)
tk nha b
a; 7/2+33/7-75/14=20/7
b: 9/2+1/2:11/2=9/2+1/11=101/22
\(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\)
=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\)
=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)
2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)
\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\)
\(\dfrac{35}{12}-\dfrac{7}{5}\)
\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)
4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)
(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\)
6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)
7 + \(\dfrac{103}{28}\)
\(\dfrac{299}{28}\)
câu b trần nhật quỳnh tính sai rồi. Nhân chia trước cộng trừ sau mà
4\(\frac{1}{2}\)+\(\frac{1}{2}\): 5\(\frac{1}{2}\)
=\(\frac{9}{2}\)\(+\)\(\frac{1}{2}\)\(\div\)\(\frac{11}{2}\)
=\(\frac{9}{2}\)\(+\)\(\frac{1}{2}\)\(\times\)\(\frac{2}{11}\)
=\(\frac{9}{2}\)\(+\)\(\frac{1}{11}\)
=\(\frac{101}{22}\)
\(3\frac{1}{2}=\frac{7}{2};4\frac{5}{7}=\frac{33}{7};5\frac{5}{14}=\frac{75}{14}\)
\(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}\)
\(=\frac{7}{2}+\frac{33}{7}-\frac{75}{14}\)
\(=\frac{49}{14}+\frac{66}{14}-\frac{75}{14}\)
\(=\frac{115}{14}-\frac{75}{14}\)
\(=\frac{40}{14}=\frac{20}{7}\)