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Ta có: \(\frac{x+1}{-2}=\frac{-8}{x+1}\Rightarrow\left(x+1\right)^2=\left(-2\right).\left(-8\right)\)
\(\Rightarrow\left(x+1\right)^2=16\)
\(\Rightarrow x+1=\pm4\)
Nếu x + 1 = 4 thi x = 3
Nếu x + 1 = -4 thì x = -5
Vậy x = {-5;3}
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\(\frac{x-2}{2}-\frac{1+x}{3}=\frac{4-3x}{4}-1\)
\(\Leftrightarrow\frac{3\left(x-2\right)-2\left(1+x\right)}{6}=\frac{4-3x-4}{4}\)
\(\Leftrightarrow\frac{3x-6-2-2x}{6}=-\frac{3x}{4}\)
\(\Leftrightarrow\frac{x-8}{6}=-\frac{3x}{4}\)
\(\Leftrightarrow4x-32=-18x\)
\(\Rightarrow x=\frac{16}{11}\)
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x-1/4.x=1/2
x.(1-1/4)=1/2
x.(4/4-1/4)=1/2
x.3/4=1/2
x=1/2÷3/4
x=1/2.4/3
x=2/3
Vậy x=2/3
ta có (x+x)+(1/2+1/4)
=2x3/4=1
2x=1-3/4
2x=1/4
x=1/4:4=1/16
Đs 1/16
8 (x-4)=0
=>x-4=0
=>x=0+4
=>x=4
Đáp số: x=4
\(8\left(x-4\right)=0\)
\(x-4=0:8=0\)
\(x=0+4=4\)
Vậy \(x=4\)