Question

[BYE BYE]

Tim cac so mu X, biet rang luy thua 5^2x-1 thoa man dieu kien:

           100<5^2x-1<5⁶

Answer 1

[Lang Tu Hoa Hao]

ta co:100>5^2 va 100 < 5^3

=> 5^2< 5^2x-1< 5^6

=> 2< 2x-1< 6

den do tu giai

Answer 2

[Trà My]

100<5^2x-1<5⁶

=>5².4<5^2x-1<6⁶

=>2<2x-1<6

=>2x-1\(\in\){3;4;5}

=>2x\(\in\){4;5;6}

=>x\(\in\){2;3}