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a: \(\dfrac{-4}{8}=\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}\)
=>\(\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}=\dfrac{-1}{2}\)
=>\(\left\{{}\begin{matrix}x=\left(-10\right)\cdot\dfrac{\left(-1\right)}{2}=5\\y=\dfrac{-7\cdot2}{-1}=14\\z=\dfrac{-24\cdot\left(-1\right)}{2}=\dfrac{24}{2}=12\end{matrix}\right.\)
b: \(\dfrac{-3}{6}=\dfrac{x}{-2}=\dfrac{-18}{y}=\dfrac{-z}{24}\)
=>\(\dfrac{x}{-2}=\dfrac{-18}{y}=\dfrac{z}{-24}=\dfrac{-1}{2}\)
=>\(\dfrac{x}{2}=\dfrac{18}{y}=\dfrac{z}{24}=\dfrac{1}{2}\)
=>\(x=2\cdot\dfrac{1}{2}=1;y=18\cdot\dfrac{2}{1}=36;z=\dfrac{24}{2}=12\)
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\(\frac{x}{2}=\frac{8}{y}=\frac{-12}{z}=2\)
1. \(\frac{x}{2}=\frac{2}{1}\)Mà \(\frac{2}{1}=\frac{4}{2}\)\(\Rightarrow x=4\)
Ta có :\(\frac{4}{2}=\frac{8}{y}\)\(\Leftrightarrow\frac{8}{4}=\frac{8}{y}\)\(\Rightarrow y=4\)
Ta lại có : \(\frac{-12}{z}=\frac{2}{1}\)\(\Leftrightarrow\frac{-12}{z}=\frac{-12}{-6}\)\(\Rightarrow z=-6\)
K/l : Vậy \(x=4;y=4;z=-6\)
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Xét : \(\frac{-4}{8}=\frac{x}{-10}\Leftrightarrow8x=40\Leftrightarrow x=5\)
\(\frac{-4}{8}=\frac{-7}{y}\Leftrightarrow-4y=-56\Leftrightarrow y=14\)
\(\frac{-4}{8}=\frac{z}{24}\Leftrightarrow-96=8z\Leftrightarrow z=-12\)
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