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(x-32+11)=(21-33+7)
(x-32+11)=-5
x-33 =-5-11
x-33 =-16
x =-16+33
x =17
Ta có : ( x - 32 + 11 ) = ( 21 - 33 + 7 )
=> x - 32 + 11 = -5
=> x - 32 = -5 - 11
=> x - 32 = -16
=> x = -16 + 32
=> x = -16
Vậy x = -16
![](https://rs.olm.vn/images/avt/0.png?1311)
b;\(\frac{x}{17}=\frac{60}{204}\)
=> \(x=60.17:204=5\)
c; \(6+\frac{x}{33}=\frac{7}{11}\)
=> \(6=\frac{7}{11}-\frac{x}{33}\)
=> \(6=\frac{21}{33}-\frac{x}{33}\)
=> \(6=\frac{21-x}{33}\)
=> \(21-x=198\)
=> \(x=21-198\)
=> \(x=-117\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,11-(15+21)=x-(25-9)
11-15-21=x-25+9
-x=-25+9-11+15+21
-x=9
x=-9
b,9-25=(7-x)-(25+7)
-16=7-x-32
x=7-32+16
x=-9
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(x+5=20-\left(12-7\right)\)
\(\Rightarrow x+5=20-5\)
\(\Rightarrow x+5=15\)
\(\Rightarrow x=15-5\)
\(\Rightarrow x=10\)
b) \(15-\left(3+2x\right)=2^2\)
\(\Rightarrow3+2x=15-4\)
\(\Rightarrow3+2x=11\)
\(\Rightarrow2x=11-3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=\dfrac{8}{2}\)
\(\Rightarrow x=4\)
c) \(-11-\left(19-x\right)=50\)
\(\Rightarrow19-x=-11-50\)
\(\Rightarrow19-x=-61\)
\(\Rightarrow x=61+19\)
\(\Rightarrow x=80\)
d) \(159-\left(25-x\right)=43\)
\(\Rightarrow25-x=159-43\)
\(\Rightarrow25-x=116\)
\(\Rightarrow x=25-116\)
\(\Rightarrow x=-91\)
e) \(\left(79-x\right)-43=-\left(17-52\right)\)
\(\Rightarrow\left(79-x\right)-43=52-17\)
\(\Rightarrow79-x-43=35\)
\(\Rightarrow36-x=35\)
\(\Rightarrow x=1\)
f) \(\left(7+x\right)-\left(21-13\right)=32\)
\(\Rightarrow7+x-8=32\)
\(\Rightarrow x-1=32\)
\(\Rightarrow x=32+1\)
\(\Rightarrow x=33\)
g) \(-x+20=-15+8+13\)
\(\Rightarrow-x+20=6\)
\(\Rightarrow x=20-6\)
\(\Rightarrow x=14\)
h) \(-\left(-x+13-142\right)+18=55\)
\(\Rightarrow x-13+142+18=55\)
\(\Rightarrow x+147=55\)
\(\Rightarrow x=55-147\)
\(\Rightarrow x=-92\)
x-32+11=-12+7
x-32+11=-5
x+11=-5+32
x+11=27
x=27-11
x=16
x-32+11 =21-33+7
x-32+11 = -12+7
x-32+11 = -5
x-32 = -5 -11
x-32 = -16
x = -16 + 32
x = -16