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\(44.179+20^2-79.44\\ =44\left(179-79\right)+400\\ =44.100+400\\ =100\left(44+4\right)=4800\\ 3.4^2:\left[500-\left(7.35+125\right)\right]\\ =3.16:\left[500-370\right]\\ =48:130=\dfrac{24}{65}\\ 187+\left[921-\left(921+887\right)\right]\\ =187+921-921-887\\ =187-887=-700\)
44. 179+ 202 - 79.44 3. 42 : [500- (7.35+125)]
= 44. 179+400 - 79.44 = 3. 16: [500- (245+125)]
= 44. (179-79) +400 = 48: [ 500-370 ]
= 44. 100+400 = 48:130
= 4400+400 = 0, 369...
= 4800
187+ [ 921-( 921+887) = 187+ [921- 1808]
= 187+ (-159)
= 28
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a ) 4 7 + 1 7 + 3 7 = 8 7 b ) 4 7 + − 3 7 + − 1 2 + 1 2 = 1 7
c ) − 27 10 + − 3 10 + 1 4 + 5 4 + 13 2 = − 3 + 3 2 + 13 2 = 5 d ) 8 5 + 7 5 + − 11 4 + − 9 4 + − 7 20 = 3 − 5 + − 7 20 = − 47 20 e ) 7 5 + − 1 15 + − 11 3 + 11 2 + 1 6 + ( − 2 ) = 4 3 + 2 + ( − 2 ) = 4 3
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mik ko hiểu cách bạn ghi
a) 187+ [921-(921+887)] ??? ri hã
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a) x + 1 5 = − 4 9
x = − 4 9 − 1 5 x = − 29 45
b) 5 7 − x = − 9 21
x = 5 7 + 9 21 x = 8 7
a) Ta có : \(16^{19}=\left(2^4\right)^{19}=2^{76}\)
\(8^{15}=\left(2^3\right)^{15}=2^{45}\)
mà \(76>45\)
\(\Rightarrow2^{76}>2^{45}\)
hay \(16^{19}>8^{15}\)
b) Ta có : \(625^2=\left(5^4\right)^2=5^8\)
\(125^6=\left(5^3\right)^6=5^{18}\)
mà \(8< 18\)
\(\Rightarrow5^8< 5^{18}\)
hay \(625^2< 125^6\)
c) Ta có : \(3^{14}< 3^{21}< 4^{21}\)
\(\Rightarrow3^{14}< 4^{21}\)
d) Ta có : \(729^3=\left(3^6\right)^3=3^{18}\)
\(9^{21}=\left(3^2\right)^{21}=3^{42}\)
mà \(18< 42\)
\(\Rightarrow3^{18}< 3^{42}\)
hay \(729^3< 9^{21}\)