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mk vẫn thắc mắc sao 1.2.3.....9- 1.2.3.4.8^2 lại bằng 1.2.3.4.5....9
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1.2.3...9-1.2.3...8-1.2.3...8^2\)
\(=\left(1.2.3...8\right).9-1.2.3...8-1.2.3..8.8\)
\(=\left(1.2.3....8\right)8-1.2.3.4...8\)
\(=1.2.3...8.8-1.2.3...8.8\)
\(=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1.2.3.......9-1.2.3...8-1.2.3....82
=1.2.3.......9-1.2.3.........8-1.2.3....8.8
= 1.2.3....8(9-1-8)
=1.2.3......8.0
=0
![](https://rs.olm.vn/images/avt/0.png?1311)
1.2.3...9-1.2.3...8-1.2.3....7.8^2
= 8!(9-1)-7! . 8^2
=8! . 8-7! . 8^2=7!8^2-7!8^2=0
Hỏi bài này nhiều quá rồi đấy , mà rõ ràng mình đã giải , bạn còn chưa tích mà
![](https://rs.olm.vn/images/avt/0.png?1311)
1.2.3....9 - 1.2.3....8 - 1.2.3....8^2=1.2.3.....8. (9-1- 1.2.3....8)=1.2.3.....8.(-40312)=40320-(-40312)=80632
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài làm
1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
= 1.2.3...8.( 9 - 1 - 8 )
= 1.2.3...8 .0
= 0
_Chúc_Bạn_Hok_Tốt_^^
\(1.2.3....9-1.2.3...8-1.2.3...7.8^2=1.2.3....8\left(9-1-8\right)=1.2.3....8.0=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1.2.3.....9-1.2.3.....8-1.2.3.....7.8^2\)
\(=1.2.3.....8\left(9-1-8\right)\)
\(=1.2.3.....8\cdot0\)
\(=0\)
1.2.3.....9−1.2.3.....8−1.2.3.....7.821.2.3.....9−1.2.3.....8−1.2.3.....7.82
=1.2.3.....8(9−1−8)=1.2.3.....8(9−1−8)
=1.2.3.....8⋅0=1.2.3.....8⋅0
=0
=0 k mik nhé