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Ta có: \(1,\left(279\right)=1+279.0,\left(001\right)=1+279.\frac{1}{999}=\frac{142}{111}\);
\(2,\left(720\right)=2+720.0,\left(001\right)=2+720.\frac{1}{999}=\frac{302}{111}\)
\(\Rightarrow1,\left(279\right)+2,\left(720\right)=\frac{142}{111}+\frac{302}{111}=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1,(279)=1+0,(279)=1+279/999=142/111
2,(720)=2+0,(720)=2+720/999=302/111
=>1,(279)+2,(720)=142/111+302/111=444/111=4
tick nhé
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1,(279)+2,(720)=\(\frac{142}{111}+\frac{302}{111}=\frac{444}{111}=4\)
1,(279) + 2(720) = 2 + 1 + [0,(279 + 0,(720)]
= 3 + 1 = 4
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1,(279)+2,(720)
=\(\left(1+\frac{279}{999}\right)+\left(2+\frac{720}{999}\right)\)
=\(\frac{142}{111}+\frac{302}{111}\)
=4
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![](https://rs.olm.vn/images/avt/0.png?1311)
(-2)[-1/(1/2)][-1/(1/3)]...[-1/(1/2010...=2.(-1)(-2)(-3)...(-2010) có 2010 thừa số âm (chẵn thừa số âm (chẵn thừa số âm )=>tich dương .
(-2)[-1/(1/2)[-1/(1/3)]....[-1/(1/2010...=2.1.2.3.......2010=2.2010 !
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