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A = 2015 x ( 2014 + 1)
A = 2015 x 2014 + 2015
B = 2014 x ( 2015 + 1 )
B= 2014 x 2015 + 2014
Vậy A > B
tick nha
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![](https://rs.olm.vn/images/avt/0.png?1311)
a=2014.(2015+1)=2014.2015+2014
b=2015.(2014+1)=2015.2014+2015
=> b>a
A = 2014.2016 = ( 2015 - 1 ).( 2015 + 1 )
B = 2015.2015
A = 2015. ( 2015 + 1 ) - ( 2015 + 1 )
A = 2015.2015 + 2015 - 2015 -1
A = 2015. 2015 - 1 < 2015. 2015 = B
Vậy: A < B
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ( − 225 ) . ( − 336 ) > 0
b) ( − 112 ) .2. ( − 26 ) . ( − 321 ) < 0
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a, m = 19.90 = 19.3.30 = 57.30
n = 31.60 = 31.2.30 = 62.30
n > m
b, 2011 < 2015
2012 < 2015
2011.2012 < 2015.2015
p < q
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
A=2017.2017=(2016+1)2017
A=2017.2016+2017
Ta lại có :
B=2016.2018=2016(2017+1)
B=2016.2017+2016
Mà 2017>2016
\(\Rightarrow\)2017.2016+2017>2017.2016+2016
\(\Rightarrow\)A>B
A = 2015 x ( 2014 + 1)
A = 2015 x 2014 + 2015
B = 2014 x ( 2015 + 1 )
B= 2014 x 2015 + 2014
Vậy A > B
tick nha
\(A=2015.2015=2014.2015-2015\)
\(B=2014.2016=2014.2015-2014\)
Vi\(2015.2015=2014.2015-2015\)<\(2014.2016=2014.2015-2014\)
=> A>B
Chuan 100% do