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\(S=\dfrac{27+4500+135+550.2}{2+4+6+...+14+16+18}\)
\(S=\dfrac{4527+135+1100}{\left(2+18\right).9.2}\)
\(S=\dfrac{4662+1100}{20.9.2}\)
\(S=\dfrac{5762}{90}\)
\(S=\dfrac{2881}{45}\)
`S=(27+4500+135+550.2)/(2+4+6+…+14+16+18)`
`S=(27+4500+135+1100)/((2+18)+(4+16)+…+(8+12)+10)`
`S=((27+135)+(4500+1100))/(20+20+…+20+10)` `(`Có `4` số hạng `20)`
`S=(162+5600)/(20.4+10)`
`S=5762/90`
`S=2881/45`
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
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\(\frac{27+4500+135+550.2}{2+4+6+...+16+18}\)= \(\frac{27+4500+135+1100}{\left(18+2\right).\left[\left(18-2\right):2+1\right]:2}\)= \(\frac{5762}{20.19:2}\)=\(\frac{5762}{190}\)=\(\frac{2881}{95}\)
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Xét tử số:
27.4500+135.550.2=27.4500+27.5.550.2=27.4500+27.5500=27.10000=270000
Xét mẫu số:
2+4+6+...+16+18
Ta thấy:dãy số này có QLC=2.
=>SSH là:(18-2):2+1=9(số)
=>Tổng là:(2+18).9:2=90.
Vậy ps cần tìm là:270000/90=3000
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Cho A=3\(^1\)+3\(^2\)+...+3\(^{2006}\)
a)Rút gọn A
b)Tìm x để 2A+3=3\(^x\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=\frac{27+4500+135+550.2}{2+4+6+...+14+16+18}\)
\(S=\frac{4527+135+1100}{\left(2+18\right).9:2}=\frac{4662+1100}{20.9:2}=\frac{5762}{90}=\frac{2881}{45}\)
\(B=\frac{27+4500+135+1100}{\frac{\left(2+18\right).9}{2}}=\frac{5762}{10.9}=\frac{2881}{45}\)