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17/5×1/2×10/17×-1/8
17/10×-10/136
-170/1360
-1/8
5/54+10/63+5/63+15/63
5/54+15/63+15/63
5/54+30/63
315/3402+1620/3402
1935/3402
\(\Leftrightarrow\frac{-2}{17}\le\frac{x}{17}\le\frac{2}{17}\Rightarrow x\in\left(-2;-1;0;1;2\right)\)
\(\Leftrightarrow\frac{-1}{24}\le\frac{x}{24}\le\frac{5}{24}\Rightarrow x\in\left(-1;0;1;2;3;4;5\right)\)
2 câu sau tự làm nha
\(-\frac{5}{17}+\frac{3}{17}\le\frac{x}{17}\le\frac{13}{17}+-\frac{11}{17}\)
\(\frac{-2}{17}\le\frac{x}{17}\le\frac{2}{17}\)
=> \(x\in\left\{-2;-1;0;1;2\right\}\)
\(M=\frac{17}{5}\cdot\frac{-31}{125}\cdot\frac{1}{2}\cdot\frac{10}{17}\cdot\frac{-1}{2^3}\)
\(M=\frac{17}{5}\cdot\frac{-31}{125}\cdot\frac{1}{2}\cdot\frac{10}{7}\cdot\frac{-1}{8}\)
\(M=\left(\frac{17}{5}\cdot\frac{10}{17}\cdot\frac{1}{2}\right)\cdot\frac{-31}{125}\cdot\frac{-1}{8}\)
\(M=1\cdot\frac{31}{1000}=\frac{31}{1000}\)
\(P=\frac{6}{7}\cdot\frac{8}{13}+\frac{6}{9}\cdot\frac{9}{7}-\frac{3}{13}\cdot\frac{6}{7}=\frac{6}{7}\cdot\frac{8}{13}+\frac{6}{7}\cdot1-\frac{3}{13}\cdot\frac{6}{7}\)
\(=\frac{6}{7}\left(\frac{8}{13}+1-\frac{3}{13}\right)=\frac{6}{7}\left(\frac{8}{3}+\frac{13}{13}-\frac{3}{13}\right)=\frac{6}{7}\cdot\frac{18}{13}=\frac{108}{91}\)
\(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)
\(=\frac{11}{125}-\left(\frac{17}{18}-\frac{8}{18}\right)+\left(\frac{17}{14}-\frac{10}{14}\right)\)
\(=\frac{11}{125}-\frac{1}{2}+\frac{1}{2}\)
\(=\frac{11}{125}+\left(\frac{1}{2}-\frac{1}{2}\right)\)= \(\frac{11}{125}\)
b) \(\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(=\left(6-5-3\right)+\left(\frac{7}{3}-\frac{5}{3}-\frac{2}{3}\right)+\left(\frac{1}{2}+\frac{3}{2}-\frac{5}{2}\right)\)
\(=-2+0+\frac{-1}{2}\)
= \(-2-\frac{-1}{2}=-\left(2+\frac{1}{2}\right)=-2\frac{1}{2}\)
A = \(\frac{\frac{\frac{5+3.3-1.12}{12}}{3.6-5+2.2}+}{6}+\frac{16\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}\right)}{17\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}\right)}=\frac{\frac{\frac{5+9-12}{12}}{18-5+4}}{6}+\frac{16}{17}=\frac{2}{12}.\frac{6}{17}+\frac{16}{17}=\frac{1}{17}.\frac{6}{17}=1\)
A=\(\frac{\frac{5}{12}+\frac{9}{12}-\frac{12}{12}}{\frac{18}{6}-\frac{5}{6}+\frac{4}{6}}+\frac{16.\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}\right)}{17.\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}\right)}\)
=\(\frac{\frac{1}{6}}{\frac{17}{6}}+\frac{16}{17}\)
=\(\frac{1}{17}+\frac{16}{17}\)
=1
\(M=\frac{17}{5}\cdot\frac{1}{2}\cdot\frac{10}{17}\cdot\frac{-1}{2^3}\)
\(=\frac{17}{5}\cdot\frac{10}{17}\cdot\frac{1}{2}\cdot\frac{-1}{8}\)
\(=\frac{17\cdot10}{5\cdot17}\cdot\frac{1\cdot(-1)}{2\cdot8}\)
\(=\frac{1\cdot2}{1\cdot1}\cdot\frac{1\cdot(-1)}{2\cdot8}\)
\(=2\cdot\frac{-1}{16}=\frac{2\cdot(-1)}{16}=\frac{1\cdot(-1)}{8}=\frac{-1}{8}\)
\(M=\frac{17}{5}.\frac{1}{2}.\frac{10}{17}.\frac{-1}{2^3}\)
\(\Leftrightarrow M=\frac{17}{5}.\frac{1}{2}.\frac{10}{17}.\frac{-1}{8}\)
\(\Leftrightarrow M=\left(\frac{17}{5}.\frac{10}{17}\right)\left(\frac{1}{2}-\frac{-1}{8}\right)\)
\(\Leftrightarrow M=2.\frac{-1}{16}\)
\(\Leftrightarrow M=\frac{-2}{16}=\frac{-1}{8}\)
\(\frac{3}{5}\cdot\frac{18}{17}+\frac{3}{5}\cdot\frac{9}{17}-\frac{3}{5}\cdot\frac{10}{17}\)
\(=\frac{3}{5}\left[\frac{18}{17}+\frac{9}{17}-\frac{10}{17}\right]\)
\(=\frac{3}{5}\left[\frac{18+9-10}{17}\right]=\frac{3}{5}\cdot1=\frac{3}{5}\)
Bài làm
\(\frac{3}{5}.\frac{18}{17}+\frac{3}{5}.\frac{9}{18}-\frac{3}{5}.\frac{10}{17}\)
\(=\frac{3}{5}.\left(\frac{18}{17}+\frac{9}{18}-\frac{10}{17}\right)\)
~ Đến đây tự tính, tối rồi, lười k mún tính . tính trong ngoặc trc nha~
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