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\(9+\frac{x}{13}-x=\frac{5}{6}\)
\(\Leftrightarrow\frac{x}{13}-x=\frac{5}{6}-9\)
\(\Leftrightarrow x\left(\frac{1}{13}-1\right)=\frac{5}{6}-\frac{54}{6}\)
\(\Leftrightarrow\frac{-12}{13}x=\frac{-50}{6}\)
\(\Leftrightarrow x=\frac{-50}{6}\div\frac{-12}{13}\)
\(\Leftrightarrow x=\frac{50}{6}\times\frac{13}{12}\)
\(\Leftrightarrow x=\frac{650}{72}=\frac{325}{36}\)
\(9+\frac{x}{13}-x=\frac{5}{6}\)
\(\Rightarrow9+\frac{x}{13}-\frac{13x}{13}=\frac{5}{6}\)
\(\Rightarrow9+\frac{x-13x}{13}=\frac{5}{6}\)
\(\Rightarrow\frac{x-13x}{13}=\frac{5}{6}-9\)
\(\Rightarrow\frac{x-13x}{13}=-\frac{49}{6}\)
\(\Rightarrow x-13x=-\frac{49}{6}\cdot13=-\frac{637}{6}\)
\(\Rightarrow-12x=-\frac{637}{6}\)
\(\Rightarrow x=-\frac{637}{6}:(-12)=\frac{637}{72}\)
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1.
7/15:(1/2-9/10xX)-1/6=13/6
=>7/15:(1/2-9/10xX)=13/6+1/6
=>7/16:(1/2-9/10xX)=7/3
=>1/2-9/10xX=7/16:7/3
=>1/2-9/10xX=3/16
=>9/10xX=1/2-3/16
=>9/10xX=5/16
=>X=5/16:9/10
=>X=25/72
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\(\dfrac{9+x}{13-x}=\dfrac{5}{6}\\ \Rightarrow5\left(13-x\right)=6\left(9+x\right)\\ \Rightarrow65-5x=54+6x\\ \Rightarrow6x+5x=65-54\\ \Rightarrow11x=11\\ \Rightarrow x=1\)
Vậy x = 1
ĐKXĐ: \(x\ne13\)
\(\dfrac{9+x}{13-x}=\dfrac{5}{6}\)
\(\Leftrightarrow\dfrac{6\left(9+x\right)}{6\left(13-x\right)}=\dfrac{5\left(13-x\right)}{6\left(13-x\right)}\)
\(\Rightarrow6\left(9+x\right)=5\left(13-x\right)\)
\(\Leftrightarrow54+6x=65-5x\)
\(\Leftrightarrow6x+5x=65-54\)
\(\Leftrightarrow11x=11\)
\(\Leftrightarrow x=1\) (thỏa mãn ĐKXĐ)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{9+x}{13-x}=\frac{5}{6}\)
<=> (9+x).6 = (13 - x).5
<=> 54 + 6x = 65 - x.5
<=> 11x = 65 - 54
<=> x = 11 : 11
<=> x = 1
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có : \(\frac{35}{91}\)= \(\frac{5}{13}=\frac{x}{13}\Rightarrow x=5\)
b, ta có
<=>6 (9+x)=5 (13-x)
<=>54+6x=65-5x
<=>6x+5x=65-54
<=>11x=11
<=>x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{9+x}{13-x}=\frac{5}{6}\)
\(\Leftrightarrow6\left(9+x\right)=5\left(13-x\right)\)
\(\Leftrightarrow54+6x=65-5x\)
\(\Leftrightarrow54-65=-5x-6x\)
\(\Leftrightarrow-11=-11x\)
\(\Leftrightarrow x=\frac{11}{11}\)
\(\Leftrightarrow x=1\)
\(\frac{9+x}{13-x}=\frac{5}{6}\)
\(\Rightarrow\text{ }6\left(9+x\right)=5\left(13-x\right)\)
\(\Rightarrow\text{ }54+6x=65-5x\)
\(\Rightarrow\text{ }54-65=-5x-6x\)
\(\Rightarrow\text{ }-11=-11x\)
\(\Rightarrow\text{ }x=-11\text{ : }\left(-11\right)\)
\(\Rightarrow\text{ }x=1\)