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Vì \(-\frac{13}{72}< 0\frac{1}{10000}\Rightarrow-\frac{13}{72}< \frac{1}{10000}\)
Vì \(-\frac{5299}{5199}< -1< -\frac{1963}{2017}\Rightarrow-\frac{5299}{5199}< -\frac{1963}{2017}\)
Ta có :\(-\frac{1111}{4444}=-\frac{1}{4}=-\frac{15}{60}\)
Vì\(-\frac{15}{61}>-\frac{15}{60}\Rightarrow-\frac{15}{61}>-\frac{1111}{4444}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{1}{3}-\frac{3}{4}-\frac{-3}{5}+\frac{1}{72}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)
\(\Rightarrow A=\frac{1}{3}+\frac{-3}{4}+\frac{3}{5}+\frac{1}{72}+\frac{-2}{9}+\frac{-1}{36}+\frac{1}{15}\)
\(\Rightarrow A=\left(\frac{1}{3}+\frac{3}{5}+\frac{1}{15}\right)+\left(\frac{-3}{4}+\frac{-2}{9}+\frac{-1}{36}\right)+\frac{1}{72}\)
\(\Rightarrow A=1+\left(-1\right)+\frac{1}{72}\)
\(\Rightarrow A=0+\frac{1}{72}\)
\(\Rightarrow A=\frac{1}{72}\)
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a) Ta có :\(\left(\frac{-1}{5}\right)^{300}=\frac{-1^{300}}{5^{300}}=\frac{1}{125^{100}}\)
\(\left(\frac{-1}{3}\right)^{500}=\frac{-1^{500}}{3^{500}}=\frac{1}{243^{100}}\)
Mà \(\frac{1}{125^{100}}>\frac{1}{243^{100}}\)
\(\Rightarrow\left(\frac{-1}{5}\right)^{300}>\left(\frac{-1}{3}\right)^{500}\)
b)Ta có :\(2^{90}=\left(2^{15}\right)^6=32768^6\)
\(5^{36}=\left(5^6\right)^6=15625^6\)
Vì \(32768^6>15625^6\Rightarrow2^{90}>5^{36}\)
a.Ta có: \(\left(\frac{-1}{5}\right)^{300}=\left(\frac{-1}{5}^3\right)^{100}=\left(\frac{-1}{125}\right)^{100}=\left(\frac{1}{125}\right)^{100}\)
\(\left(\frac{-1}{3}\right)^{500}=\left(\frac{-1}{3}^5\right)^{100}=\left(\frac{-1}{243}\right)^{100}=\left(\frac{1}{234}\right)^{100}\)
Mà: \(\frac{1}{125}>\frac{1}{234}\Rightarrow\left(\frac{1}{125}\right)^{100}>\left(\frac{1}{234}\right)^{100}\)
Vậy \(\left(\frac{-1}{5}\right)^{300}>\left(\frac{-1}{3}\right)^{500}\)
b.Ta có: \(2^{90}=\left(2^{10}\right)^9=1024^9\)
\(5^{36}=\left(5^4\right)^9=625^9\)
Mặt khác: \(1024>625\Rightarrow1024^9>625^9\)
Vậy \(2^{90}>5^{36}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{3}-\frac{3}{4}-\left(-\frac{3}{5}\right)+\frac{1}{72}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}=\left(\frac{1}{3}+\frac{3}{5}+\frac{1}{15}\right)-\left(\frac{3}{4}+\frac{2}{9}+\frac{1}{36}\right)+\frac{1}{72}=1-1+\frac{1}{72}=\frac{1}{72}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=\frac{1}{3}-\frac{3}{4}+\frac{3}{5}+\frac{1}{72}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)
\(B=\left(\frac{1}{3}+\frac{3}{5}+\frac{1}{15}\right)+\left(\frac{-3}{4}-\frac{2}{9}-\frac{1}{36}+\frac{1}{72}\right)\)
\(B=\left(\frac{5}{15}+\frac{9}{15}+\frac{1}{15}\right)+\left(\frac{-54}{72}-\frac{16}{72}-\frac{2}{72}+\frac{1}{72}\right)\)
\(B=1-\frac{71}{72}\)
\(B=\frac{72}{72}-\frac{71}{72}\)
\(B=\frac{1}{72}\)
vay \(B=\frac{1}{72}\)
\(\frac{-1}{36}\)và \(\frac{-1}{72}\)
Quy đồng ta được \(\frac{-2}{72}\)và \(\frac{-1}{72}\)
\(\frac{-2}{72}\)< \(\frac{-1}{72}\)
\(\frac{-1}{36}\)< \(\frac{-1}{72}\)
k cho mk nha