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S=1+9+92+93+...+92017
9S =(90+9+92+93+...+92017).2
9S =9+92+93+94+...+92017+92018
9S-S =(9+92+93+94+...+92017+92018)-(90+9+92+93+...+92017)
8S =92018-90
S =(92018-90):8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=1+9+9^2+...+9^{2017}\)
\(\Rightarrow9S=9+9^2+9^3+...+9^{2018}\)
\(\Rightarrow9S-S=8S=\left(9+9^2+9^3+...+9^{2018}\right)-\left(1+9+9^2+...+9^{2017}\right)\)
\(8S=9^{2018}-1\)
\(\Rightarrow S=\frac{9^{2018}-1}{8}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=1+9+9^2+....+9^{2017}\)
\(9S=9.\left(1+9+9^2+...+9^{2017}\right)\)
\(9S=9+9^2+9^3+...+9^{2018}\)
\(8S=9S-S=\left(9+9^2+9^3+...+9^{2018}\right)-\left(1+9+9^2+....+9^{2017}\right)\)
\(8S=9^{2018}-1\)
\(S=\left(9^{2018}-1\right)\div8=\frac{9^{2018}-1}{8}\)
Vậy S = \(\frac{9^{2018}-1}{8}\)
S = 1 + 9 + 9\(^2\)+ . . . + 9\(^{2017}\)
9S = 9 + 9\(^2\)+ 9\(^3\)+ . . . + 9\(^{2018}\)
S = [ 9 + 9\(^2\)+ 9\(^3\)+ . . . + 9\(^{2018}\)] - [ 1 + 9 + 9\(^2\)+ . . . + 9\(^{2017}\)
S = [ 9 - 9 ] + [ 9\(^2\)- 9\(^2\) ] + [ 9\(^3\)- 9\(^3\)] + . . . + [ 9\(^{2017}\)- 9\(^{2017}\)] + [ 9\(^{2018}\)- 1 ]
S = 9\(^{2018}\)- 1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=1+9+9^2+...+9^{2017}.\)
\(S=\left(1+9\right)+\left(9^2+9^3\right)+....+\left(9^{2016}+9^{2017}\right)\)
\(S=10+10.9^2+...+10.9^{2016}\)
\(S=1.\left(1+9^2+....+9^{2016}\right)⋮10\)
\(\Rightarrow S⋮10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
=> 9S=9+9^2+9^3+...+9^2018
=> 9S-S=8S=(9+9^2+9^3+...+9^2018)-(1+9+9^2+9^3+...+9^2017)
=> 8S=9+9^2+...+9^2018-1-9-9^2-...-9^2017
=> 8S=9^2018-1
=> S=(9^2018-1)/8
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Tính các tổng sau:
1, S=1-2+3_4+..+25-26
S =-1+3-5+7-...-53+55 ( có 28 số hạng )
= (-1+3)+(-5+7)+...+(-53+55) ( có 28:2=14 nhóm )
= 2+2+...+2
= 2 . 14
= 28
\(S=1+9+9^2+.....+9^{2017}\)
\(9S=9+9^2+9^3+.....+9^{2017}+9^{2018}\)
\(9S-S=8S=9^{2018}-1\)
\(S=\frac{9^{2018}-1}{8}\)