![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Dễ mà
ta có: \(\sqrt{17}>\sqrt{16}=4\)
Tương tự: \(\sqrt{26}>\sqrt{25}=5\)
Suy ra: \(\sqrt{17}+\sqrt{26}+1>4+5+1=10\)
Mặt khác:
\(\sqrt{99}< \sqrt{100}=10\)
Vậy \(\sqrt{17}+\sqrt{26}+1>\sqrt{99}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\sqrt{1}+\sqrt{4}+\sqrt{9}+....+\sqrt{400}+\sqrt{441}\)
= 1+2+3+...+21=231
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\sqrt{17}+\sqrt{26}+1>\sqrt{16}+\sqrt{25}+1=4+5+1=10\)
\(\sqrt{99}\sqrt{99}\)
\(\sqrt{17}+\sqrt{26}+1>\sqrt{16}+\sqrt{25}+1=4+5+1=10=\sqrt{100}>\sqrt{99}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\sqrt{17}\)>\(\sqrt{16}\)=4
và \(\sqrt{26}\)>\(\sqrt{25}\)=5
nên \(\sqrt{17}\)+\(\sqrt{16}\)+1>4+5+1
\(\sqrt{17}\)+\(\sqrt{16}\)+1>10=\(\sqrt{100}\)>\(\sqrt{99}\)
Vậy \(\sqrt{17}\)+\(\sqrt{26}\)+1>\(\sqrt{99}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
\(\sqrt{26}+\sqrt{17}>\sqrt{25}+\sqrt{16}=5+4=9\)
Từ đó ta suy ra:
\(\sqrt{26}+\sqrt{17}>9\left(đpcm\right)\)
(Tíck cho mìk vs nha!)
Ta có: \(\sqrt{17}+\sqrt{26}+\sqrt{101}>\sqrt{16}+\sqrt{25}+\sqrt{100}\)
\(\Rightarrow\sqrt{17}+\sqrt{26}+\sqrt{101}>4+5+10\)
\(\Rightarrow\sqrt{17}+\sqrt{26}+\sqrt{101}>19\)
Mà \(\sqrt{441}=21\)
=> Có sai đề không?