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4 tháng 12 2023

chịu

 

2 tháng 8 2019

= 25/49 *( 21/29-7/29) +24/49 * 15/29

=25/49*14/29+ 24/49*15/29

   BẠN TỰ LÀM TIẾP NHA

  study well

2 tháng 8 2019

\(\frac{25}{49}.\frac{21}{29}-\frac{25}{49}.\frac{7}{29}+\frac{24}{49}.\frac{15}{29}\)

\(=\frac{25}{49}.\left(\frac{21}{29}-\frac{7}{29}\right)+\frac{24}{49}.\frac{15}{29}\)

\(=\frac{25}{49}.\frac{14}{29}+\frac{24}{49}.\frac{15}{29}\)

\(=\left(\frac{25}{49}+\frac{24}{49}\right).\left(\frac{14}{29}+\frac{15}{29}\right)\)

\(=1.1=1\)

23 tháng 7 2016

a) \(\frac{x}{3}-\frac{10}{21}=-\frac{1}{7}\)

\(\Rightarrow\frac{x}{3}=-\frac{1}{7}+\frac{10}{21}\)

\(\Rightarrow\frac{x}{3}=\frac{7}{21}\)

\(\Rightarrow\frac{x}{3}=\frac{1}{3}\)

\(\Rightarrow x=1\)

\(x-25\%=\frac{1}{2}\)

\(\Rightarrow x-\frac{1}{4}=\frac{1}{2}\)

\(\Rightarrow x=\frac{1}{2}+\frac{1}{4}\)

\(\Rightarrow x=\frac{3}{4}\)

c) \(-\frac{5}{6}+\frac{8}{3}+-\frac{29}{6}\le x\le-\frac{1}{2}+2+\frac{5}{2}\)

\(\Rightarrow-3\le x\le4\)

\(\Rightarrow x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)

24 tháng 7 2016

a)x/3-10/21=-1/7

 x/3=-1/7+10/21

x/3=1/3

=> x= 1

   

20 tháng 7 2016

a ) \(\frac{x}{3}-\frac{10}{21}=-\frac{1}{7}\)

\(\frac{x}{3}=-\frac{1}{7}+\frac{10}{21}\)

\(\frac{x}{3}=-\frac{3}{21}+\frac{10}{21}\)

\(\frac{x}{3}=-\frac{13}{21}\)

\(x:3=-\frac{13}{21}\)

\(x=-\frac{13}{21}.3\)

8 tháng 3 2022

a, bổ sung đề 

 \(\dfrac{29-x}{21}+1+\dfrac{27-x}{23}+1+\dfrac{25-x}{25}+1+\dfrac{23-x}{27}+1+\dfrac{21-x}{29}+1=0\)

\(\Leftrightarrow\dfrac{50-x}{21}+\dfrac{50-x}{23}+\dfrac{50-x}{25}+\dfrac{50-x}{27}+\dfrac{50-x}{29}=0\)

\(\Leftrightarrow\left(50-x\right)\left(\dfrac{1}{21}+\dfrac{1}{23}+\dfrac{1}{25}+\dfrac{1}{27}+\dfrac{1}{29}\ne0\right)=0\Leftrightarrow x=50\)

9 tháng 4 2017

\(a,\frac{5}{7}+x=\frac{29}{21}\)

               \(x=\frac{29}{21}-\frac{5}{7}\)

               \(x=\frac{2}{3}\)

\(b,\frac{15}{2}-x=\frac{21}{14}\)

                 \(x=\frac{15}{2}-\frac{21}{14}\)

                 \(x=\frac{6}{1}\Leftrightarrow6\)

9 tháng 4 2017

a) 5/7 +x= 29/21

=> x= 29/21 - 5/7

=>x= 14/21= 2/3

b) 15/2 -x= 21/14

<=> 15/2 -x= 3/2

=> x= 15/2 -3/2

=>x= 6

23 tháng 4 2017

ta có 1/3=10/30

1/21+1/22+...+1/30 có 10 p/số

mà 1/21>1/30

1/22>1/30

....

1/29>1/30

1/30=1/30

=>1/21+..1/30>1/30+....1/30 có 10 phân số 

=>1/21+...1/30>1/3

23 tháng 4 2017

Ta có: \(\frac{1}{21}< \frac{1}{30}\)

\(\frac{1}{22}< \frac{1}{30}\)

......

\(\frac{1}{29}< \frac{1}{30}\)

\(\Rightarrow S< \frac{1}{30}+\frac{1}{30}+...+\frac{1}{30}\)(có 10 p/s)
\(\Rightarrow S< \frac{1}{30}.10=\frac{10}{30}=\frac{1}{3}\)

Vậy S < 1/3

1 tháng 2 2019

a,\(\frac{21}{25}.\frac{11}{9}.\frac{5}{7}=\frac{21.11.5}{25.9.7}=\frac{3.7.11.5}{5^2.3^2.7}=\frac{11}{5.3}=\frac{11}{15}\)

b,\(\frac{5}{23}.\frac{17}{26}+\frac{5}{23}.\frac{9}{26}=\frac{5}{23}.\left(\frac{17}{26}+\frac{9}{26}\right)=\frac{5}{23}.1=\frac{5}{23}\)

c, \(\left(\frac{3}{29}-\frac{1}{5}\right).\frac{29}{3}=\frac{3}{29}.\frac{29}{3}-\frac{1}{5}.\frac{29}{3}=1-\frac{29}{15}=-\frac{14}{15}\)

1 tháng 2 2019

a , \(\frac{21}{25}\times\frac{11}{9}\times\frac{5}{7}\) 

\(=\frac{21\times11\times5}{25\times9\times7}\)

\(=\frac{3\times7\times11\times5}{5\times5\times3\times3\times7}\) 

\(=\frac{11}{5\times3}\) 

\(=\frac{11}{15}\) 

b ,   \(\frac{5}{23}\times\frac{17}{26}+\frac{5}{23}\times\frac{9}{26}\) 

\(=\frac{5}{23}\times\left(\frac{17}{26}+\frac{9}{26}\right)\)

\(=\frac{5}{23}\times\frac{26}{26}\) 

\(=\frac{5}{23}\times1\) 

\(=\frac{5}{23}\) 

c , \(\left(\frac{3}{29}-\frac{1}{5}\right)\times\frac{29}{3}\) 

\(=\frac{3}{29}\times\frac{29}{3}-\frac{1}{5}\times\frac{29}{3}\) 

\(=1-\frac{29}{15}\) 

2 tháng 4 2018

a)\(\left(\frac{3}{29}-\frac{1}{5}\right)\cdot\frac{29}{3}\)

\(=\left(\frac{3}{29}\cdot\frac{29}{3}\right)-\left(\frac{1}{5}\cdot\frac{29}{3}\right)\)

\(=1-\frac{29}{15}\)

\(=\frac{-14}{15}\)

b)\(\frac{16}{15}\cdot\frac{-5}{14}\cdot\frac{54}{24}\cdot\frac{56}{21}\)

=\(=\frac{16\cdot\left(-5\right)\cdot54\cdot56}{15\cdot14\cdot24\cdot21}\)

\(=\frac{2^4\cdot\left(-5\right)\cdot2\cdot3^3\cdot2^3\cdot7}{3\cdot5\cdot7\cdot2\cdot2^3\cdot3\cdot7}\)

\(=2^4\)

c)\(\frac{37}{7}\cdot\frac{8}{11}+\frac{37}{7}\cdot\frac{5}{11}-\frac{37}{7}\cdot\frac{2}{11}\)

\(=\frac{37}{7}\cdot\left(\frac{8}{11}+\frac{5}{11}-\frac{2}{11}\right)\)

\(=\frac{37}{7}\cdot1\)

\(=\frac{37}{7}\)

Đúng nhớ k nhen!

2 tháng 4 2018

b)\(-2^4\)nãy mk nhầm