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\(\frac{8.7.5}{11.8.7}=\frac{5}{11}\)

21 tháng 3 2020

\(\frac{8.7.5}{11.8.7}=\frac{5}{11}\)

Học tốt

5 tháng 2 2017

a.\(\frac{3\cdot4\cdot7}{12\cdot8\cdot9}\)\(\frac{3\cdot4\cdot7}{3\cdot4\cdot8\cdot9}\)\(\frac{7}{72}\) 

b. \(\frac{4\cdot5\cdot6}{12\cdot10\cdot8}\)\(\frac{4\cdot5\cdot2\cdot3}{3\cdot4\cdot5\cdot2\cdot8}\)\(\frac{1}{8}\) 

c.\(\frac{5\cdot6\cdot7}{12\cdot14\cdot15}\)\(\frac{5\cdot6\cdot7}{2\cdot6\cdot2\cdot7\cdot3\cdot5}\)\(\frac{1}{12}\)

5 tháng 2 2017

a, \(\frac{3.4.7}{12.8.9}\)\(\frac{3.4.7}{3.4.8.9}\)\(\frac{7}{72}\)

b, \(\frac{4.5.6}{12.10.8}\)\(\frac{4.5.6}{3.4.2.5.8}\)\(\frac{1}{8}\)

c, \(\frac{5.6.7}{12.14.15}\)\(\frac{5.6.7}{2.6.2.7.3.5}\)\(\frac{1}{12}\)

\(A=\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}\)

\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)

\(A=\frac{1}{2}-\frac{1}{8}=\frac{3}{8}\)

30 tháng 7 2020

\(A=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\\ \)

\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{7}-\frac{1}{8}\)

\(=\frac{1}{2}-\frac{1}{8}\)

\(=\frac{4}{8}-\frac{1}{8}\\ =\frac{3}{8}\)

Chúc bn học thiệt giỏi nhé!

31 tháng 7 2020

\(\frac{10}{11}:\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)

\(=\frac{10}{11}:\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)

\(=\frac{10}{11}:\left(\frac{1}{3}-\frac{1}{11}\right)\)

\(=\frac{10}{11}:\frac{8}{33}=\frac{10}{11}.\frac{33}{8}\)

\(=\frac{15}{4}\)

31 tháng 7 2020

Trả lời:

\(\frac{10}{11}\div\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)

\(=\frac{10}{11}\div\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)

\(=\frac{10}{11}\div\left(\frac{1}{3}-\frac{1}{11}\right)\)

\(=\frac{10}{11}\div\frac{8}{33}\)

\(=\frac{10}{11}\times\frac{33}{8}\)

\(=\frac{15}{4}\)

1 tháng 8 2020

\(\frac{10}{11}:\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)

\(=\frac{10}{11}:\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)

\(=\frac{10}{11}:\left(\frac{1}{3}-\frac{1}{11}\right)\)

\(=\frac{10}{11}:\left(\frac{11}{33}-\frac{3}{33}\right)\)

\(=\frac{10}{11}:\frac{8}{33}\)

\(=\frac{15}{4}\)

Học tốt

1 tháng 8 2020

\(\frac{10}{11}:\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)

\(=\frac{10}{11}:\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)

\(=\frac{10}{11}:\left(\frac{1}{3}-\frac{1}{11}\right)\)

\(=\frac{10}{11}:\frac{8}{33}\)

\(=\frac{10}{11}.\frac{33}{8}\)

\(=\frac{15}{4}\)

12 tháng 2 2016

\(\frac{\text{30.25.7.8}}{\text{75.8.12.14}}=\frac{\left(30:6\right).\left(25:25\right).\left(7:7\right).\left(8:8\right)}{\left(75:25\right).\left(8:8\right).\left(12:6\right).\left(14:7\right)}=\frac{5..1.1.1}{3.1.2.2}=\frac{5}{12}\)

25 tháng 4 2016

\(\frac{1}{1.3.5}+\frac{1}{3.5.7}+\frac{1}{5.7.9}+...+\frac{1}{99.101.103}\)

=\(\frac{1}{4}\left(\frac{4}{1.3.5}+\frac{4}{3.5.7}+\frac{4}{5.7.9}+...+\frac{4}{99.101.103}\right)\)

=\(\frac{1}{4}\left(\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{99.101}-\frac{1}{101.103}\right)\)

=\(\frac{1}{4}\left(\frac{1}{1.3}-\frac{1}{101.103}\right)\)

=\(\frac{1}{4}.\frac{10406}{31209}\)

=\(\frac{5230}{62418}\)

25 tháng 4 2016

tui chịu thôi

16 tháng 5 2017

= 6.7.4.4.3.3.2.5.11

11.2.4.5.3.6.16.2.7.2.3,2

= 1

16

16 tháng 5 2017

6x7x8x9x10x11 22x20x18x16x14x12 1 2 2 1 1 2 1 2 2 1 1 2 = 1 64

12 tháng 2 2016

\(\frac{30.25.7.8}{75.8.12.14}=\frac{5.6.5.5.7.8}{5.5.3.8.6.2.7.2}=\frac{5}{3.2.2}=\frac{5}{12}\)

12 tháng 2 2016

30 x 25 x 7 x 8   = 2 x 25 x 7 x 8 x 1        =  1 

75 x 8 x 12 x 14    25 x 3 x 8 x 12 x 7 x 2    36