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a)
\(\left(\frac{1}{8}x-\frac{3}{8}\right)\left(2x^2+3\right)=0\)
+) 1/8x - 3/8 = 0
1/8x = 3/8
x = 3
+) 2x^2 + 3 = 0
2x^2 = -3
x^2 = -3/2
mà mũ chẵn luôn lớn hơn hoặc bằng 0 => loại
b)
\(\left|\frac{5}{3}x-1\right|+\frac{4}{5}\le\frac{4}{5}\)
\(\left|\frac{5}{3}x-1\right|\le0\)
mà \(\left|\frac{5}{3}x-1\right|\ge0\forall x\)
=> 5/3x - 1 = 0
5/3x = 1
x = 3/5
Vậy,..........
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a) 3x - 2 = 0 => 3x = 2 => x = 2/3
b) 2x - 1 = 0 => 2x = 1 => x = 1/2
c) 5 ( 4+2x) = 8+5x
<=> 20 + 10x = 8 + 5x
<=> 10x - 5x = 8 - 20
<=> 5x = -12
x = -12/5
d) \(\frac{1}{2}+\frac{3}{4}x=6-\frac{4}{5}x\)
\(\frac{3}{4}x+\frac{4}{5}x=6-\frac{1}{2}\)
\(\frac{31}{20}x=\frac{11}{2}\)
\(x=\frac{11}{2}:\frac{31}{20}=\frac{110}{31}\)
e) 3 + 2x = 4 - 8x
<=> 2x + 8x = 4 - 3
10 x = 1
x = 1/10
f \(5+\frac{1}{2}\left(x+5\right)=3\)
\(\frac{1}{2}\left(x+5\right)=3-5=-2\)
\(x+5=-2:\frac{1}{2}=-4\)
\(x=-4-5=1\)
Vậy ......
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a. \(\frac{3}{5}+x=\frac{5}{6}\)
=> \(x=\frac{5}{6}-\frac{3}{5}\)
=> \(x=\frac{7}{30}\)
b. \(\left(3\frac{1}{2}+2x\right).\frac{8}{3}=\frac{16}{3}\)
=> \(3\frac{1}{2}+2x=\frac{16}{3}:\frac{8}{3}=2\)
=> \(2x=2-3\frac{1}{2}=2-\frac{7}{2}=-\frac{3}{2}\)
=> \(x=-\frac{3}{2}:2\)
=> \(x=-\frac{3}{4}\)
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e)\(\frac{1}{3}\left(2x-5\right)=-\frac{2}{3}-\frac{3}{2}\)
\(\frac{1}{3}\left(2x-5\right)=-\frac{13}{6}\)
\(2x-5=-\frac{13}{2}\)
\(2x=\frac{-3}{2}\)
\(x=-\frac{3}{4}\)
\(\frac{2x}{3}=\frac{x+5}{8}\Rightarrow2x.8=3.\left(x+5\right)\)
\(\Rightarrow16x=3x+15\)
\(\Rightarrow16x-3x=15\)
\(\Rightarrow13x=15\Rightarrow x=\frac{15}{13}\)
Vậy x = 15/13
\(\frac{2x}{3}=\frac{x+5}{8}\)
\(\Leftrightarrow2x\cdot8=3\cdot\left(x+5\right)\)
\(16x=3x+15\)
\(13x=15\)
\(x=\frac{15}{13}\)