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\(a,\frac{-8}{15}.\left(-30\right).\frac{15}{-8}.\frac{9}{10}\)
\(=-\left(\frac{8}{15}.\frac{15}{8}\right).\left(30.\frac{9}{10}\right)\)
\(=-1.27
=-27\)
\(b,2\frac{1}{18}.\frac{23}{24}.\frac{9}{37}.\frac{48}{-15}\)
\(=\frac{-37.23.9.48}{18.24.37.15}=\frac{23}{15}\)
c, chịu rồi
\(A=\left[\frac{1\frac{11}{31}\cdot4\frac{3}{7}-\left(15-6\frac{1}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-5\frac{1}{3}\right)}\cdot\left(-1\frac{14}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{\frac{42}{31}\cdot\frac{31}{7}-\left(15-\frac{19}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-\frac{16}{3}\right)}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{6-\left(15-\frac{2}{3}\right)}{\frac{29}{6}+\frac{10}{9}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{6-\frac{43}{3}}{\frac{107}{18}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{-\frac{25}{3}}{\frac{107}{18}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\frac{50}{31}\cdot\frac{31}{50}=1\)
\(\frac{-11}{14}-\frac{-4}{...}=\frac{-3}{14}\)
\(\frac{-11}{14}+\frac{4}{...}=\frac{-3}{14}\)
\(\frac{4}{...}=\frac{-3}{14}-\frac{-11}{14}\)
\(\frac{4}{...}=\frac{-3}{14}+\frac{11}{14}\)
\(\frac{4}{...}=\frac{8}{14}\)
\(\frac{4}{...}=\frac{4}{7}\)
\(\frac{1}{...}-\frac{-2}{15}=\frac{7}{15}\)
\(\frac{1}{...}+\frac{2}{15}=\frac{7}{15}\)
\(\frac{1}{...}=\frac{7}{15}-\frac{2}{15}\)
\(\frac{1}{...}=\frac{5}{15}\)
\(\frac{1}{...}=\frac{1}{3}\)
Hok tốt !!!!!!!!!