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![](https://rs.olm.vn/images/avt/0.png?1311)
a.
\(A=5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9=5.2^{30}.3^{18}-2^2.3^{20}.2^{27}\)
\(=5.2^{30}.3^{18}-3^{20}.2^{29}=2^{29}.3^{18}.\left(5.2-3^2\right)=2^{29}.3^{18}\)
\(B=5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6=5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}=5.2^{28}.3^{19}-7.2^{29}.3^{18}\)
\(=2^{28}.3^{18}.\left(5.3-7.2\right)=2^{28}.3^{18}\)
=> \(A:B=\left(2^{29}.3^{18}\right):\left(2^{28}.3^{18}\right)=\frac{\left(2^{29}.3^{18}\right)}{\left(2^{28}.3^{18}\right)}=2\)
b. kiểm tra lại đề bài nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :C= 2181-729+243.81-27
=2052+19683-27
C=21108
D=\(3^2.9^2.243+18.243.324.243\)
=9.81.243+18.243.324.243
=177147+344373768
=344550915
Ta có : C:D=21108:344550915=0,00006
![](https://rs.olm.vn/images/avt/0.png?1311)
C = 2181 . 93 + 243 . 92
C = 2181 . 92 . 9 + 243 . 92
C = ( 19 629 + 243 ) . 92
C = 19872 . 92
C = 1 609 632
![](https://rs.olm.vn/images/avt/0.png?1311)
C=2181.729+243.3.27.27=2181.729+729.729=729.(2181+729)=729.2910
D=3.3.81.243+6.3.243.324+723.729=243.729+729.1944+723.729=729.(243+1944+723)=2910.729
=>C:D=1
![](https://rs.olm.vn/images/avt/0.png?1311)
a, A= 5x415 x 99 - 4x320x 89 = 5x230x318-22x 227x320
=229x318(2x5-32)=229x318
B=5x29x619-7x229x276=5x29x219x3197x229x318
=238x318(5x3-7x2)=228-318
->A:B= 229x318:228:318=2