Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(2\frac{3}{13}\cdot\frac{26}{58}\cdot4\cdot2\frac{15}{24}\cdot\frac{8}{21}=\frac{29}{13}\cdot\frac{26}{58}\cdot4\cdot\frac{21}{8}\cdot\frac{8}{21}=\frac{29\cdot26\cdot4\cdot21\cdot8}{13\cdot58\cdot8\cdot21}=\frac{1\cdot2\cdot4\cdot1\cdot1}{1\cdot2\cdot1\cdot1}=\frac{1\cdot4}{1}=4\)
\(2\times\frac{3}{13}\times\frac{26}{58}\times4\times2\frac{15}{24}\times\frac{8}{21}\)
\(=\left(2\times4\right)\times\left(\frac{3}{13}\times\frac{26}{58}\times\frac{63}{24}\times\frac{8}{21}\right)\)
\(=8\times\left(\frac{3\times26\times63\times8}{13\times58\times24\times21}\right)\)
\(=8\times\left(\frac{3\times13\times2\times7\times3\times3\times8}{13\times29\times2\times3\times8\times7\times3}\right)\)
\(=8\times\left(\frac{2\times3\times8}{29}\right)\)
\(=8\times\left(\frac{48}{29}\right)\)
\(=\frac{8\times48}{29}\)
\(=\frac{384}{29}=13\frac{7}{29}\)
Bài 1:
\(4.\left(\frac{-1}{2}\right)^2-2.\left(\frac{-1}{2}\right)^2+3.\left(\frac{-1}{2}\right)+1\)
\(=4.\frac{1}{4}-2.\frac{1}{4}+3.\left(\frac{-1}{2}\right)+1\)
\(=1-\frac{1}{2}-\frac{3}{2}+1\)
\(=0\)
Bài 2:
a) \(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\Rightarrow7\left(37-x\right)=3\left(x+13\right)\)
\(\Rightarrow259-7x=3x+39\)
\(\Rightarrow259-39=3x+7x\)
\(\Rightarrow220=10x\)
\(\Rightarrow x=22\)
d) \(\frac{3^2.3^8}{27^3}=3^x\)
\(\Rightarrow\frac{3^{10}}{\left(3^3\right)^3}=3^x\)
\(\frac{\Rightarrow3^{10}}{3^9}=3^x\)
\(\Rightarrow3=3^x\)
\(\Rightarrow x=1\)
Hok tốt nha^^
\(2\frac{3}{13}.\frac{27}{58}.2\frac{15}{24}.\frac{8}{21}:\frac{3}{7}=\frac{29}{13}.\frac{27}{58}.\frac{63}{24}.\frac{8}{21}:\frac{3}{7}=\frac{27}{26}.\frac{63}{24}.\frac{8}{21}:\frac{3}{7}=\frac{567}{208}.\frac{8}{21}:\frac{3}{7}=\frac{27}{26}:\frac{3}{7}=\frac{63}{26}\)
3697256 : 794580