1/\(\frac{4\sqrt{2}}{2+\sqrt{2}}-\frac{4\sqrt{2}}{2-\sqrt{2}}\)
2/ \(\frac{2}{\sqrt{2}}+\sqrt{2}-2\sqrt{18}+\sqrt{\left(1-\sqrt{2}\right)^2}\)
3/ \(9\sqrt{\frac{2}{3}}+5\sqrt{54}-\sqrt{\frac{1}{2}-\frac{1}{3}}\)
4/ \(\sqrt{4+2\sqrt{2}}.\sqrt{4-2\sqrt{2}}.\left(\sqrt{8}-\sqrt{2}\right)\)
5/ \(\sqrt{14-6\sqrt{5}}+\sqrt{3-2\sqrt{2}}+\sqrt{7-2\sqrt{10}}\)
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Đọc tiếp
1/\(\frac{4\sqrt{2}}{2+\sqrt{2}}-\frac{4\sqrt{2}}{2-\sqrt{2}}\)
2/ \(\frac{2}{\sqrt{2}}+\sqrt{2}-2\sqrt{18}+\sqrt{\left(1-\sqrt{2}\right)^2}\)
3/ \(9\sqrt{\frac{2}{3}}+5\sqrt{54}-\sqrt{\frac{1}{2}-\frac{1}{3}}\)
4/ \(\sqrt{4+2\sqrt{2}}.\sqrt{4-2\sqrt{2}}.\left(\sqrt{8}-\sqrt{2}\right)\)
5/ \(\sqrt{14-6\sqrt{5}}+\sqrt{3-2\sqrt{2}}+\sqrt{7-2\sqrt{10}}\)
1, \(=\frac{4\sqrt{2}\left(2-\sqrt{2}\right)}{2^2-\sqrt{2}^2}-\frac{4\sqrt{2}\left(2+\sqrt{2}\right)}{2^2-\sqrt{2}^2}\)
=\(\frac{4\sqrt{2}\left(2-\sqrt{2}\right)}{2}-\frac{4\sqrt{2}\left(2+\sqrt{2}\right)}{2}\)
=\(2\sqrt{2}\left(2-\sqrt{2}\right)-2\sqrt{2}\left(2+\sqrt{2}\right)\)
=\(4\sqrt{2}-4-4\sqrt{2}-4\)
=-8
2, =\(\sqrt{2}+\sqrt{2}-2.3\sqrt{2}+\left|1-\sqrt{2}\right|\)
= \(-4\sqrt{2}+1-\sqrt{2}\) = \(1-5\sqrt{2}\)
3, =\(9\sqrt{\frac{2.2}{3.2}}+5\sqrt{9.6}-\sqrt{\frac{1}{6}}\)
=\(3\sqrt{6}+15\sqrt{6}-\frac{1}{6}\sqrt{6}\)
=\(\frac{107}{6}\sqrt{6}\)
4, =\(\sqrt{\left(4+2\sqrt{2}\right)\left(4-2\sqrt{2}\right)}.\left(2\sqrt{2}-\sqrt{2}\right)\)
= \(\sqrt{4^2-\left(2\sqrt{2}\right)^2}.\sqrt{2}\)
= \(\sqrt{16-8}.\sqrt{2}\)
= \(\sqrt{8}.\sqrt{2}=\sqrt{16}=4\)
5, = \(\sqrt{9-2.3.\sqrt{5}+5}+\sqrt{1-2.1.\sqrt{2}+2}+\sqrt{5-2.\sqrt{2}.\sqrt{5}+2}\)
\(=\sqrt{\left(3-\sqrt{5}\right)^2}+\sqrt{(1-\sqrt{2})^2}+\sqrt{\left(\sqrt{5}-\sqrt{2}\right)^2}\)\(=\left|3-\sqrt{5}\right|+\left|1-\sqrt{2}\right|+\left|\sqrt{5}-\sqrt{2}\right|\)
\(=3-\sqrt{5}+1-\sqrt{2}+\sqrt{5}-\sqrt{2}\)
\(=4-2\sqrt{2}\)