giúp mình với ; lim\(\dfrac{4-3^n}{2.3^n+2}\),lim\(\dfrac{3^{n+1}-2^n}{2-2.3^n}\)
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a, X : 3 x 48 + X : 4 x 36 = 1500
X x \(\dfrac{1}{3}\) x 48 + X x \(\dfrac{1}{4}\) x 36 = 1500
X x 16 + X x 9 = 1500
X x ( 16 + 9 ) = 1500
X x 25 = 1500
X = 1500 : 25
X = 60
b, X + 7,5 x X : 5 + X : 2 x 9 = 315
X + 7,5 x X x \(\dfrac{1}{5}\) + X x \(\dfrac{1}{2}\) x 9 = 315
X + X x 1,5 + X x 4,5 = 315
X x ( 1 + 1,5 + 4,5 ) = 315
X x 7 = 315
X = 315 : 7
X = 45
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`x : 1/2 + x : 1/3 + x : 0,1 - x xx 5 = 100`
`x xx 2 + x xx 3 + x xx 10 - x xx 5 = 100`
`x xx ( 2 + 3 + 10 - 5 ) = 100`
`x xx 10 = 100`
`x = 100 : 10`
`x = 10`
Vậy `x = 10`
Lời giải:
$x:\frac{1}{2}+x:\frac{1}{3}+x:0,1-x\times 5=100$
$x\times 2+x\times 3+x\times 10-x\times 5=100$
$x\times (2+3+10-5)=100$
$x\times 10=100$
$x=100:10=10$
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
$x:\frac{1}{2}+x:\frac{1}{3}+x:0,1-x\times 5=100$
$x\times 2+x\times 3+x\times 10-x\times 5=100$
$x\times (2+3+10-5)=100$
$x\times 10=100$
$x=100:10$
$x=10$
a)lim\(\dfrac{4-3^n}{2.3^n+2}\)=lim\(\dfrac{4.\dfrac{1^n}{3^n}-\dfrac{3^n}{3^n}}{2.\dfrac{3^n}{3^n}+2\dfrac{1^n}{3^n}}=\)\(lim\dfrac{4.(\dfrac{1}{3})^n-1}{2.1+2.(\dfrac{1}{3})^n}=\dfrac{4.0-1}{\dfrac{2+2.0}{ }}=\dfrac{-1}{2}\)
b) lim\(\dfrac{3^{n+1}-2^n}{2-2.3^n}=lim\dfrac{3^n.3-2^n}{2-2.3^n}=lim\dfrac{3.\dfrac{3^n}{3^n}-\left(\dfrac{2}{3}\right)^n}{2.\left(\dfrac{1}{3}\right)^n-2.\dfrac{3^n}{3^n}}=\dfrac{3.1-0}{2.0-2.1}=\dfrac{-3}{2}\)
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