5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+6+5+5+5+5+5++5+5++5+5++5+5+5+++8+8+8+6+6+5+5+5+5+5+5+5+5+5+5++5+5+5+5+5+5++5+5+5
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5 + 6 + 9 + 5 + 6 + 2 + 5 +5 + 5+ 5 + 5 + 5 + 5 + 2 + 8 + 9 =87
vậy số đó là 87
.
Tìm x,biết
\(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}\cdot\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=8^x\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}\)
\(=\dfrac{4.4^5.6.6^5}{3.3^5.2.2^5}\)
\(=\dfrac{4^6.6^6}{3^6.2^6}\)
\(=\dfrac{2^6.2^6.2^6.3^6}{3^6.2^6}\)
\(=2^{12}=2^{3^4}=8^4=8^x\)
Vậy x = 4
45+45+45+4535+35+35.65+65+65+65+65+6525+2545+45+45+4535+35+35.65+65+65+65+65+6525+25
=4.45.6.653.35.2.25=4.45.6.653.35.2.25
=46.6636.26=46.6636.26
=26.26.26.3636.26=26.26.26.3636.26
=212=234=84=8x=212=234=84=8x
Vậy x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=8^{\left|2x+6\right|}\)
\(\Leftrightarrow\frac{4.\left(4^5\right)}{3.\left(3^5\right)}.\frac{6.\left(6^5\right)}{2.\left(2^5\right)}=8^{\left|2x+6\right|}\)
\(\Leftrightarrow\frac{4^6.6^6}{3^6.2^3}=8^{\left|2x+6\right|}\)
\(\Leftrightarrow\frac{\left(2^2\right)^6.\left(2.3\right)^6}{3^6.2^3}=8^{\left|2x+6\right|}\)
\(\frac{2^{12}.2^6.3^6}{3^6.2^3}=\frac{2^{18}.3^6}{3^6.2^3}=\frac{2^{15}.1}{1.1}=2^{15}=8^{\left|2x+6\right|}\)
=> 215=(23)|2x+6|
215=23|2x+6|
<=> 3|2x+6|=15
|2x+6|=15:3
|2x+6|=5
\(\Rightarrow\orbr{\begin{cases}2x+6=5\\2x+6=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{-11}{2}\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
\(\text{VT}=\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}\)
\(=\frac{4.4^5}{3.3^5}.\frac{6.6^5}{2.2^5}=\frac{4^6.6^6}{3^6.2^6}=\frac{2^{12}.2^6.3^6}{3^6.2^6}=2^{12}\)
Do đó: \(8^{|2x+6|}=2^{12}\Leftrightarrow 2^{3|2x+6|}=2^{12}\)
\(\Leftrightarrow 3|2x+6|=12\Leftrightarrow |2x+6|=4\)
\(\Rightarrow\left[{}\begin{matrix}2x+6=4\\2x+6=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=-5\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{4^5+4^5+4^5}{3^5+3^5+3^5}\cdot\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=8^x\)
\(\Rightarrow\frac{3\cdot2^{10}}{3^6}\cdot\frac{6^6}{2^6}=8^x\)
\(\Rightarrow\frac{4^5}{3^5}\cdot3^6=8^x\)
\(\Rightarrow4^5\cdot3=8^x\)
hình như sai đề hoặc mik làm sai:))
![](https://rs.olm.vn/images/avt/0.png?1311)
Phương pháp giải:
Nhẩm lại bảng nhân trong phạm vi đã học rồi điền kết quả vào chỗ trống.
Lời giải chi tiết:
5 × 2 = 10 | 5 × 3 = 15 | 5 × 4 = 20 |
5 × 9 = 45 | 5 × 8 = 40 | 5 × 7 = 35 |
5 × 5 = 25 | 5 × 6 = 30 | 5 × 10 = 50 |
5 × 1 = 5 | 1 × 5 = 5 | 4 × 5 = 20 |
![](https://rs.olm.vn/images/avt/0.png?1311)
N=(5+5^2)+5^2x(5+5^2)+5^4x(5+5^2)+5^6x(5+5^2)+5^8x(5+5^2)
N=30+5^2x30+5^4x30+5^6x30+5^8x30
N=(1+5^2+5^4+5^6+5^8)x30
Vì 30 chia hết cho 6 nên N chia hết cho 6.
N=(5+5^2)+5^2x(5+5^2)+5^4x(5+5^2)+5^6x(5+5^2)+5^8x(5+5^2)
N=30+5^2x30+5^4x30+5^6x30+5^8x30
N=(1+5^2+5^4+5^6+5^8)x30
Vì 30 chia hết cho 6 nên N chia hết cho 6.
hmmmmm ko rảnh để tính cái này mà bọn lớp 1 cũng phải ngồi cả 1 tiết chắc ms x
ko danh ma ai lai di ngoi ting