\(\left(\frac{1}{3}-1,35x\right)^4=\frac{625}{256}\)
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(1/3)x+1=(1/3)x
=> x+1=x
=> x-x=-1
=> 0=-1 ( vô lí )
(4/5)x=256/625
=> (4/5)x=(4/5)4
=> x=4
Vậy x=4
a) \(\left(\frac{1}{3}\right)^{x+1}=\left(\frac{1}{3}\right)^x\)
\(\left(\frac{1}{3}\right)^{x+1}-\left(\frac{1}{3}\right)^x=0\)
\(\left(\frac{1}{3}\right)^x.\left[\frac{1}{3}-1\right]=0\)
\(\Leftrightarrow\left(\frac{1}{3}\right)^x=0\) (vô lý)
=> Không có giác trị thõa mãn
b) \(\frac{256}{625}=\frac{4^4}{5^4}=\left(\frac{4}{5}\right)^4\)
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\(\left(\frac{4}{5}\right)\cdot2x=\frac{625}{256}-7\)
\(\left(\frac{4}{5}\right)\cdot2x=-\frac{1167}{256}\)
\(\frac{4}{5}\cdot x=-\frac{1167}{256}\div2\)
\(\frac{4}{5}\cdot x=-\frac{1167}{512}\)
\(x=-\frac{1167}{512}\div\frac{4}{5}\)
\(x=-2,849121094\)
\(\frac{4}{5}\times2x=\frac{625}{256}-7=-\frac{1167}{256}\)
\(\Rightarrow2x=\left(-\frac{1167}{256}\right):\frac{4}{5}=-\frac{5835}{1024}\)
\(\Rightarrow x=\left(-\frac{5835}{1024}\right):2=-2,849121094\)
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a.\(3x^2-51=-24\)
\(\Rightarrow3x^2=27\)
\(\Rightarrow x^2=9\)
\(\Rightarrow x=3\)
b.\(5x.\left(5^3\right)^2=625\)
\(\Rightarrow5x=5^5:5^{\left(3x2\right)}\)
\(\Rightarrow5x=5^5:5^6\)
\(\Rightarrow5x=5^{-1}=0,2\)
\(\Rightarrow x=0,2:5\)
\(\Rightarrow x=0,04\)
\(\left(\frac{1}{3}-1,35x\right)^4=\frac{625}{256}\)
\(\left(\frac{1}{3}-1,35x\right)^4=\left(\frac{5}{4}\right)^4\)
\(\Rightarrow\frac{1}{3}-1,35x=\frac{5}{4}\)
\(1,35x=\frac{1}{3}-\frac{5}{4}\)
\(1,35x=\frac{-11}{12}\)
\(x=\frac{-11}{12}:1,35\)
\(x=\frac{-55}{81}\)
\(\left(\frac{1}{3}-1,35x\right)^4=\frac{625}{256}\)
\(\left(\frac{1}{3}-\frac{27}{20}\cdot x\right)^4=\frac{625}{256}\)
\(\left(\frac{1}{3}-\frac{27}{20}\cdot x\right)^4=\left(\frac{5}{4}\right)^4\)
\(\Rightarrow\left(\frac{1}{3}-\frac{27}{20}\cdot x\right)=\left(\frac{5}{4}\right)^4\)vì \(\left(\frac{5}{4}\right)^4=\frac{625}{256}\)
còn lại bạn tự tính nhé