\(\frac{x-2}{4}\) =\(\frac{5+x}{3}\)
GIÚP MK NHA
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\(\frac{1}{3}\) + \(\frac{5}{6}\): \(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)
<=> \(\frac{5}{6}\):\(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)- \(\frac{1}{3}\)
<=> \(\frac{5}{6}\) : \(\left(x-2\frac{1}{5}\right)\) = \(\frac{5}{12}\)
<=> \(\left(x-2\frac{1}{5}\right)\) = \(\frac{5}{6}\) : \(\frac{5}{12}\)
,<=> \(\left(x-2\frac{1}{5}\right)\)= 2
<=. x = 2 + \(\frac{11}{5}\)
<=> x = \(\frac{21}{5}\)
Có \(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{239}}{\frac{3}{239}-\frac{3}{7}-\frac{3}{5}-\frac{3}{17}}\) : \(\frac{x}{3}\) = 2
\(\frac{2.\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{239}\right)}{-3.\left(\frac{-1}{239}+\frac{1}{7}+\frac{1}{5}+\frac{1}{17}\right)}\) : \(\frac{x}{3}\) = 2
\(\frac{-2}{3}\) : \(\frac{x}{3}\) = 2
\(\frac{-2}{3}\) . \(\frac{3}{x}\) = 2
\(\frac{-2}{x}\) = 2
\(\Rightarrow\) x = -1
Vậy x = -1
Chúc bạn học tốt !!! ^^ #Mango
\(\frac{x-2}{4}=\frac{5+x}{3}\)
=> \(\left(x-2\right).3=\left(5+x\right).4\)
\(3x-2.3=5.4+4x\)
\(3x-6=20+4x\)
\(3x-4x=20+6\)
\(\left(3-4\right)x=26\)
\(-1x=26\)
\(x=-26\)
\(\Leftrightarrow\frac{5\left(x+5\right)-3\left(x-3\right)}{15}=\frac{5\left(x+5\right)-3\left(x-3\right)}{\left(x-3\right)\left(x+5\right)}\)
\(\Leftrightarrow\frac{2x+34}{15}=\frac{2x+34}{x^2+2x-15}\Leftrightarrow\orbr{\begin{cases}2x+34=0\\x^2+2x-15=15\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-17\\x^2+2x-30=0\end{cases}}\)
Từ đó tìm được \(S=\left\{-17;\sqrt{31}-1;-\sqrt{31}-1\right\}\)
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}+1\)
\(\Leftrightarrow\frac{20}{x+3}-8=8-\frac{18}{x+3}\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=8+8\)
\(\Leftrightarrow\frac{38}{x+3}=16\)
\(\Leftrightarrow x+3=2,375\)
\(\Leftrightarrow x=-0,625\)
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\left(\frac{18}{x+3}+1\right)\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}-1\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=7-1+8\)
\(\Leftrightarrow\frac{38}{x+3}=14\)
\(\Leftrightarrow\left(x+3\right)14=38\)
\(\Leftrightarrow14x+42=38\)
\(\Leftrightarrow14x=-4\Leftrightarrow x=-\frac{4}{14}=-\frac{2}{7}\)
Vậy \(x=-\frac{2}{7}\)
\(\frac{2.\left(x+4\right)}{\left(\sqrt{x}+1\right).\left(\sqrt{x}-4\right)}+\frac{\sqrt{x}.\left(\sqrt{x}-4\right)}{\left(\sqrt{x}+1\right).\left(\sqrt{x}-4\right)}-\frac{8.\left(\sqrt{x}+1\right)}{\left(\sqrt{x}-4\right)\left(\sqrt{x}+1\right)}\)
=\(\frac{2x+8+x-4\sqrt{x}-8\sqrt{x}-8}{\left(\sqrt{x}+1\right).\left(\sqrt{x}-4\right)}\)
=\(\frac{3x-12\sqrt{x}}{mc}\)
=\(\frac{3\sqrt{x}.\left(\sqrt{x}-4\right)}{\left(\sqrt{x-4}\right)\left(\sqrt{x}+1\right)}=\frac{3\sqrt{x}}{\sqrt{x}+1}\)
k tk mk cung lam cho
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x-3=-x+\frac{1}{5}\)
\(3x-5x+x=\frac{1}{5}+3+\frac{3}{2}\)
\(-x=\frac{47}{10}\)
\(x=\frac{-47}{10}\)
a)
\(\frac{x}{3}=\frac{y}{4}\Rightarrow\frac{x}{15}=\frac{y}{20}\)
\(\frac{y}{5}=\frac{z}{6}\Rightarrow\frac{y}{20}=\frac{z}{24}\)
=> \(\frac{x}{15}=\frac{y}{20}=\frac{z}{24}\)
Đến đây dễ rồi
b)
\(\left(\frac{x}{3}\right)^2=\frac{x}{3}\cdot\frac{x}{3}=\frac{x}{3}\cdot\frac{y}{4}=\frac{xy}{3\cdot4}=\frac{48}{12}=4=\left(\pm2\right)^2\)
TH1 : \(\frac{x}{3}=\frac{y}{4}=2\)
Sau đó tìm x và y
TH2 : \(\frac{x}{3}=\frac{y}{4}=-2\)
Sau đó lại tìm x và y
Sau cùng kết luận
Học tốt
ta có :\(\frac{x-2}{4}\) =\(\frac{5+x}{3}\)
hay \(\left(x-2\right)\) x 3 =\(\left(5+x\right)\) x 4
3x - 6 = 20+4x
3x -4x = 20 +6
-1x = 26
x = -26
k cho mình nha .
Ta có :
x-2/4=5+x/3
<=>3.(x-2)=4.(5+x)
<=>3x-6=20+4x
=>4x-3x= -6 - 20
=>x= -26
Vậy x = -26