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\(1,\dfrac{12}{25}+\dfrac{3}{5}+\dfrac{13}{25}=\left(\dfrac{12}{25}+\dfrac{13}{25}\right)+\dfrac{3}{5}=1+\dfrac{3}{5}=\dfrac{8}{5}\\ 2,\dfrac{3}{2}+\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{3}{2}+\left(\dfrac{2}{3}+\dfrac{4}{3}\right)=\dfrac{3}{2}+2=\dfrac{7}{2}\\ 3,\dfrac{3}{2}+\dfrac{7}{5}+\dfrac{3}{4}=\left(\dfrac{3}{2}+\dfrac{3}{4}\right)+\dfrac{7}{5}=\left(\dfrac{6}{4}+\dfrac{3}{4}\right)+\dfrac{7}{5}=\dfrac{9}{4}+\dfrac{7}{5}=\dfrac{45}{20}+\dfrac{28}{20}=\dfrac{73}{20}\)
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\(\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)
\(=\frac{12}{25}+\frac{15}{25}+\frac{13}{25}\)
\(=\left(\frac{12}{25}+\frac{13}{25}\right)+\frac{15}{25}\)
\(=1+\frac{15}{25}\)
\(=\frac{40}{25}\)
\(=\frac{8}{5}\)
Chúc bạn học tốt nha !!!
\(\frac{12}{25}+\frac{12}{25}+\frac{15}{25}\)(nhân cả tử và mẫu của \(\frac{3}{5}\) với 5 để chung tử là 25)
=\(\frac{12+12+15}{25}\)=\(\frac{39}{25}\)
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\(a,\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)
\(=\left(\frac{12}{25}+\frac{13}{25}\right)+\frac{3}{5}\)
\(=\frac{25}{25}+\frac{3}{5}\)
\(=1+\frac{3}{5}\)
\(=\frac{8}{5}\)
\(b,\frac{3}{2}+\frac{2}{3}+\frac{4}{3}\)
\(=\frac{3}{2}+\left(\frac{2}{3}+\frac{4}{3}\right)\)
\(=\frac{3}{2}+2\)
\(=\frac{7}{2}\)
\(c,\frac{3}{5}+\frac{7}{5}+\frac{3}{4}\)
\(=\left(\frac{3}{5}+\frac{7}{5}\right)+\frac{3}{4}\)
\(=2+\frac{3}{4}\)
\(=\frac{11}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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a. 12/25 + 3 / 5+ 13/25 = ( 12/25+13/25)+3/5 = 1 + 3/5= 8/5
b. 3/2 + 2/3 + 4/3 = 3/2+( 2/3+4/3)= 3/2 + 2=7/2
c.3/5+7/5+3/4= (3/5+7/5)+3/4 = 2+ 3/4=11/4
chúc bn hc tốt
a. 12/25+3/5+13/25
=1+3/5
=8/5
b.3/2+2/3+4/3
=3/2+2
=7/2
c.3/5+7/5+3/4
=2+3/4
=11/4
![](https://rs.olm.vn/images/avt/0.png?1311)
Tính thuận tiện :
\(\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)
= \(\frac{12}{25}+\frac{13}{25}+\frac{3}{5}\)
= \(\frac{25}{25}+\frac{3}{5}\)
= \(1+\frac{3}{5}\)
= \(\frac{5}{5}+\frac{3}{5}\)
= \(\frac{8}{5}\)
\(\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)
\(=\left(\frac{12}{25}+\frac{13}{25}\right)+\frac{3}{5}\)
\(=\frac{25}{25}+\frac{3}{5}\)
\(=1+\frac{3}{5}=\frac{8}{5}\)