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a, 219 - 7.(x + 1) = 100
7.(x + 1) = 219 - 100
7.(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
a, 219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119/7
x+1=17
x=17-1
x=16
Vậy x=16
b, 20+23(x+3)=52.4
20+8(x+3)=100
8(x+3)=100-20
8(x+3)=80
x+3=80/8
x+3=10
x=10-3
x=7
Vậy x=7
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 219 - 7(x + 1) = 100 <=> 7(x+1) = 219 - 100
<=> 7(x+1) = 119 <=> x + 1 = 119 : 7 <=> x + 1 = 17
b) (3x - 6).3 = 3434 <=> 3x - 6 = 3434 : 3 <=> 3x - 6 = 3333
<=> 3x = 27 + 6 <=> 3x = 33 <=> x = 11
a) 219−7(x+1)=100
- 7(x+ 1)= 100 - 219
- 7(x+ 1)= - 119
x+1 = -119 : (-7)
x+1 = 17
x= 17-1
x= 16
b) (3x - 6). 3 = 34
(3x - 6). 3 = 81
(3x - 6)= 81: 3
(3x - 6)= 27
3x= 27+ 6
3x= 33
x= 33:3
x= 11
b) (3x−6).3=34
![](https://rs.olm.vn/images/avt/0.png?1311)
b) \(3^x\cdot3^2+3^x=7290\)
\(3^x\left(3^2+1\right)=720\)
\(3^x\cdot10=7290\)
\(=>3^x=729=3^6\)
=> \(x=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x+5=20-\left(12-17\right)\)
\(x+5=20-\left(-5\right)\)
\(x+5=20+5\)
\(x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(219-7\left(X+1\right)=100\)
\(\Rightarrow219-7X-7=100\)
\(\Rightarrow7X=219-7-100=112\)
\(\Rightarrow X=112:7=16\)
b,\(\left(3X-6\right)x3=3^4\)
\(\Rightarrow3X-6=81:3=27\)
\(\Rightarrow3X=27+6=33\)
\(\Rightarrow X=33:3=11\)
c,\(3636:\left(12X-91\right)=36\)
\(\Rightarrow12X-91=3636:36=101\)
\(\Rightarrow12X=101+91=192\)
\(\Rightarrow X=192:12=16\)
Đúng luôn nên...hằng ngày k cho mk 3 lần, bao h đủ 100 lần thì tui nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
A)Ta có 36 chia hết cho x,45 chi hết cho x và 18 chia hết cho x,x lớn nhất nên x là ước chung lớn nhất của 36;45 và 18
=>X=9
b)Ta có:219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119:7
x+1=17
X=17-1
X=16
c)(3x-6).35=7.36
3x-6=7.36:35
3x-6=7.3
3x-6=21
3x=21+6
3x=27
3x=33
x=3
Nho v cho mình nha!!!
![](https://rs.olm.vn/images/avt/0.png?1311)
a.219 - 7(x+1) = 100
7(x+1) = 219 - 100
7(x+1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
b. (3x - 6 ) . 3 = 36
3x - 6 = 36 : 3
3x - 6 = 12
3x = 12 + 6
3x = 18
x = 18 : 3
x = 6
c.716 - ( x-143) = 659
x-143 = 716 - 659
x-143 = 57
x = 57 + 143
x = 200
b. 30 - [4(x-2)+15] = 3
4(x-2) + 15 = 30 - 3
4(x-2)+15 = 27
4(x-2) = 27 - 15
4(x-2) = 12
x-2 = 12 : 4
x-2 = 3
x = 2 + 3 = 5
e.[(8x - 12) : 4] .33 = 36
[(8x - 12) : 4] . 27 = 729
(8x - 12) : 4 = 729 : 27 = 27
8x - 12 = 27 . 4 = 108
8x = 108 + 12 = 120
x = 120 : 8 = 15
a) \(\Leftrightarrow7\left(x+1\right)=119\\ \Leftrightarrow x+1=17\\ \Leftrightarrow x=16\)
b) \(\Leftrightarrow9\left(x-2\right)=36\\ \Leftrightarrow x-2=4\\ \Leftrightarrow x=6\)
c) \(\Leftrightarrow x-143=57\\ \Leftrightarrow x=200\)
d) \(\Leftrightarrow4\left(x-2\right)+15=27\\ \Leftrightarrow4\left(x-2\right)=12\\ \Leftrightarrow x-2=3\\ \Leftrightarrow x=5\)
e) \(\Leftrightarrow\left(2x-3\right).4:4=3^3\\ \Leftrightarrow2x-3=27\\ \Leftrightarrow2x=24\\ \Leftrightarrow x=12\)
a, 45 chia hết cho x
=> x thuộc Ư(45)
=> x thuộc {1;45;3;15;5;9}
vậy...
b, x chia hết cho 12
=> x thuộc B(12)
=> x thuộc {0;12;24;36;48;60;...}
vậy.....
c, 219-7.(x+1)=100
7.(x+1)=219-100
7.(x+1)=119
x+1 = 17
x = 17-1
x = 16 vậy...
a, 45 \(⋮\)x \(\Rightarrow\)x\(\in\)Ư ( 45 ) = { \(\pm\)1;\(\pm\)3;\(\pm\)5;\(\pm\)9;\(\pm\)15;\(\pm\)45}
b, \(x⋮12\Rightarrow x\in B\left(12\right)=\left\{0;12;24;36;48....\right\}\)
\(c,219-7\left(x+1\right)=100\)
\(\Rightarrow7\left(x+1\right)=219-100\)
\(\Rightarrow7\left(x+1\right)=119\)
\(\Rightarrow x+1=119:7\)
\(\Rightarrow x+1=17\)
\(\Rightarrow x=16\)