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![](https://rs.olm.vn/images/avt/0.png?1311)
ta có \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
= \(\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2.3^{28}}\)
= \(\frac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
14 : ( 4\(\frac{2}{3}\)- 1\(\frac{5}{9}\)) + 14 : ( \(\frac{2}{3}\)+ \(\frac{8}{9}\))
= 14 : ( \(\frac{14}{3}\)- \(\frac{14}{9}\)) + 14 : ( \(\frac{6}{9}\) + \(\frac{8}{9}\))
= 14 : ( 14 - \(\frac{14}{9}\)) + 14 : \(\frac{14}{9}\)
= 14 : \(\frac{112}{9}\)+ 14 : \(\frac{14}{9}\)
= \(\frac{9}{8}\)+ 9
= \(\frac{81}{8}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
\(B=\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)........\left(1-\frac{1}{2017}\right).\left(1-\frac{1}{2018}\right)\)
\(\Rightarrow B=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.......\frac{2016}{2017}.\frac{2017}{2018}\)
Đởn giản hết sẽ còn là:
\(\Rightarrow B=\frac{1}{2018}\)