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399 + 254 x 399 - 399 x 255 : 399 x 254 + 399 x 255
1 x 399 + 254 x 399 - 399 x 255 : 399 x 254 + 399 x 255
( 1 + 254 - 255 ) x 399 : 399 x ( 254 + 255 )
0 x 399 x A
0
\(\frac{254\times399-145}{254+399\times253}=\frac{'253+1'\times399-145}{254+399\times253}\)
\(=\frac{235\times399-145}{254+399\times253}\)
\(=\frac{253\times399+254}{254+399\times253}\)
\(=1\)
Vậy: Số cần tìm là :1
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\(\frac{254x399-145}{254+399x\left(254+1\right)}\)
\(=\frac{254x399-145}{254+399x254+399}\)
\(=\frac{-145}{254+399}\)
\(=\frac{-145}{653}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
254 x399 - 145 / 254 + 399 x 255
= ( 253 + 1 ) x 399 - 145 / 254 + 399 x 255
= 253 x 399 + ( 399 - 145 )/ 254 + 399 x 255
= 254 x 399 + 255 / 254 + 399 x 155
= 1
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Câu a sai đề (sửa đề lại rồi làm tương tự câu b
Câu b
\(\frac{5932+6001\times5931}{5932\times6001-69}=\frac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}=\frac{5932+6001\times5931}{5931\times6001+6001-69}=\frac{5932+6001\times5931}{5932\times6001+5932}=1\)
\(254.399-\frac{145}{254+399.255}=101346-\frac{145}{101999}=1012031170\)
\(5932+6001.\frac{5931}{35597863}=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
#)Giải :
A, \(\frac{254x399-145}{254+399x253}\)
\(=\frac{253x399+399-145}{254+399x253}\)
\(=\frac{253x399+254}{254+399x253}\)
\(=1\)
B, \(\frac{5932+6001x5931}{5931x6001-69}\)
\(=\frac{5932+6001x5931}{\left(5931+1\right)x6001-69}\)
\(=\frac{5932+6001x5931}{5931x6001+6001-69}\)
\(=\frac{5932+6001x5932}{5932x6001+5932}\)
\(=1\)
#~Will~be~Pens~#
\(\frac{254x399-145}{254+399x253}=\frac{\left(253+1\right)x399-145}{254+399x253}=\frac{253x399+1x399-145}{254+399x253}=\frac{253x399+254}{254+399x253}\)
\(=1\)
(254 x 399 - 145) / (254 + 399 x 255)
=[( 253+1) x 399 -145]/(254 + 399 x 255)
=( 253 x 399 + 399 -145) /(254 + 399 x 255)
=(254 + 399 x 255)/(254 + 399 x 255)
=1
(254 x 399 - 145) / (254 + 399 x 255)
=[( 253+1) x 399 -145]/(254 + 399 x 255)
=( 253 x 399 + 399 -145) /(254 + 399 x 255)
=(254 + 399 x 255)/(254 + 399 x 255)
=1