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![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{1}{1x2}+\frac{1}{2x3}+...+\frac{1}{99.100}\)
\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(A=\frac{1}{1}-\frac{1}{100}=\frac{99}{100}\)
\(A=\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(A=1-\frac{1}{100}\)
\(A=\frac{99}{100}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1/1×2 + 1/2×3 + ... + 1/99×100
= 1 - 1/2 + 1/2 - 1/3 + ... + 1/99 - 1/100
= 1 - 1/100
= 99/100
Ủng hộ mk nha ♡_♡
1/1 NHÂN 2+1/1 NHÂN 3 + ... + 1/99 NHÂN 100
=1-1/2 + 1/2 -1/3 + ... +1/99-1/100
=1 - 1/100
=99/100
NHỚ K MK NHA CÁC BN CŨNG ỦNG HỘ NHÉ
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}=1-\frac{1}{100}=\frac{99}{100}\)
A = 1 - 1/2 +1/2- 1/3 +....+1/99 -1/100
= 1-1/100
=99/100
![](https://rs.olm.vn/images/avt/0.png?1311)
A = 1/1 x 2 + 1/2 x 3 + 1/3 x 4 + ... + 1/99x 100
A = 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + .... + 1/99 - 1/100
A =1 - 1/100
A = 99/100
\(\frac{1}{1\times2}+\frac{1}{2\times3}+...........+\frac{1}{99\times100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+..........+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}\)
\(=\frac{99}{100}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}=\frac{99}{100}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}=\frac{99}{100}\)(Nhớ k cho mình với nhá!)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
12 : 1/4 = 16 x 3
1/2 x 10 + 8 + 6 =19
50 + 1/2 x 5 = 75
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+.....+\frac{1}{99.100}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{99}-\frac{1}{100}\)
\(A=1-\frac{1}{100}\)
\(A=\frac{99}{100}\)