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\(\frac{22}{5}\)\(:\)\(x\)\(=\)\(\frac{44}{5}\)\(:\)\(\frac{5}{2}\)
\(\frac{22}{5}\)\(:\)\(x\)\(=\)\(\frac{88}{25}\)
\(x\)\(=\)\(\frac{22}{5}\)\(:\)\(\frac{88}{25}\)
\(x\)\(=\)\(\frac{5}{4}\)
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<=> \(\frac{12\left(x+2\right)}{x\left(x+2\right)}\)= \(\frac{12x}{\left(x+2\right)x}\)+ \(\frac{\left(x+2\right)x}{\left(x+2\right)x}\)
<=> 12x + 24 = 12x + x2 + 2x
<=> 12x - 12x -x2 + 2x + 24 = 0
<=> - x2 + 2x + 24 = 0
<=> - x2 - 4x + 6x + 24 = 0
<=> - x(x - 4) + 6(x + 4) = 0
<=> (x + 4)(- x + 6) = 0
<=> x + 4 = 0 hoặc - x + 6 = 0
<=> x = -4 hoặc x = - 6
Cho tam giác ABC trên cạnh AB lấy điểm D sao cho AD gấp đôi DB trên AC lấy điểm E sao cho AE gấp đôi EC , BE cắt CD tại G .So sánh diện tích GDB với điện tích GEC
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bui nhu quynh
Ta có : \(\frac{4}{7}\times\frac{5}{8}\times\frac{7}{12}=\frac{4\times5\times7}{7\times8\times12}=\frac{5}{24}\)
Chúc mng họk tốt ^o^
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\(\Rightarrow\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{42}\cdot\frac{x}{3}=\frac{5}{21}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{42}\cdot\frac{x}{3}=\frac{5}{21}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{6}+\frac{1}{42}\cdot\frac{x}{3}=\frac{5}{21}\)
\(\Rightarrow\frac{1}{3}+\frac{1}{42}\cdot\frac{x}{3}=\frac{5}{21}\)
\(\Rightarrow\frac{1}{42}\cdot\frac{x}{3}=\frac{5}{21}-\frac{1}{3}\)
\(\Rightarrow\frac{1}{42}\cdot\frac{x}{3}=\frac{-2}{21}\)
\(\Rightarrow\frac{x}{3}=\frac{-2}{21}\div\frac{1}{42}\)
\(\Rightarrow\frac{x}{3}=-4\)
\(\Rightarrow\frac{x}{3}=\frac{-12}{3}\)
\(\Rightarrow x=-12\)
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\(\frac{12}{5}\): x = \(\frac{8}{3}\)
x = \(\frac{8}{3}\): \(\frac{12}{5}\)
x = \(\frac{10}{9}\)
\(\frac{379-x}{12}=21,7\) Đ/S : 118,6
\(\frac{x\times4}{12}=96\) Đ/S : 288