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\(a,50\%x-0,2+x=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{1}{2}x-0,2+x=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{1}{2}x+x=\dfrac{4}{5}+0,2\)
\(\Leftrightarrow\dfrac{3}{2}x=\dfrac{4}{5}+\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{3}{2}x=1\)
\(\Leftrightarrow x=\dfrac{2}{3}\)
\(b,\left(x-\dfrac{3}{4}\right):\dfrac{1}{2}+\dfrac{3}{2}=\dfrac{25}{2}\)
\(\Leftrightarrow\left(x-\dfrac{3}{4}\right).2=\dfrac{25}{2}-\dfrac{3}{2}\)
\(\Leftrightarrow\left(x-\dfrac{3}{4}\right).2=\dfrac{22}{2}\)
\(\Leftrightarrow x-\dfrac{3}{4}=11:2\)
\(\Leftrightarrow x=\dfrac{11}{2}+\dfrac{3}{4}\)
\(\Leftrightarrow x=\dfrac{25}{4}\)
\(3^{x+4}=9^{2x-1}\)
\(\Rightarrow3^{x+4}=3^{4x-2}\)
\(\Rightarrow x+4=4x-2\)
\(\Rightarrow3x=6\Rightarrow x=2\)
Lời gải:
a. $7x+3\vdots x$
$\Rightarrow 3\vdots x$ (do $7x$ đã chia hết cho $x$)
$\Rightarrow x\in\left\{1; 3\right\}$ (do $x$ là số tự nhiên)
b.
$17-4x\vdots x$
$\Rightarrow 17\vdots x$ (do $4x$ đã chia hết cho $x$)
$\Rightarrow x\in\left\{1; 17\right\}$
Giải
Bài 1
\(1,a,-40-37-\left(-29\right)\\ =-40-37+29\\ =-77+29=-48\\ b,27+\left(-36\right)-\left(-45\right)=27-36+45\\ =-9+45\\ =36\\ c,-125-\left[\left(-18\right)-125\right]\\ =-125+18+125\\ =\left(-125+125\right)+18\\ =18\\ d,140+\left[\left(-184\right)-140\right]\\ =140-184-140\\ =\left(140-140\right)-184\\ =0-184\\ =-184\)
Bài 2
\(a,x-\left(-15\right)=-8\\ =>x+15=-8\\ =>x=-8-15\\ =>x=-23\\ b,-40-x=-35\\ =>x=\left(-40\right)-\left(-35\right)\\ =>x=-40+35\\ =>x=-5\\ c,x+\left(-50\right)=-27\\ =>x-50=-27\\ =>x=-27+50\\ =>x=23\)
1, Thực hiện phép tính:
\(a,-40+\left(-37\right)-\left(-29\right)=-77-\left(-29\right)=-48\)
\(b,27+\left(-36\right)-\left(-45\right)=-9-\left(-45\right)=36\)
\(c,-125-\left[\left(-18\right)-125\right]=-125-\left(-143\right)=18\)
\(d,140+\left[\left(-184\right)-140\right]=140+\left(-324\right)=-184\)
2, Tìm x biết:
\(a,x-\left(-15\right)=-8\)
\(x=-8+\left(-15\right)\)
\(x=-23\)
\(b,-40-x=-35\)
\(x=-40-\left(-35\right)\)
\(x=-5\)
\(c,x+\left(-50\right)=-27\)
\(x=-27-\left(-50\right)\)
\(x=23\)
a, 1.5 x ( 2 - x ) = 3.15 - 1.35
= 1.80
=> 1.5 x 2 - 1.5 x X =1.80
=> 1.5 x X = 3 - 1.80
= 2.2
=> x = 2.2 : 1.5 = 1.46
Tìm X
A ) 3,15 - 1,5 x ( 2 - X ) = 1,35
1,5 x ( 2 - X ) = 3,15 - 1,35
1,5 x ( 2 - X ) = 1.8
( 2 - X ) = 1,8 : 1,5
2 - X = 1,2
X = 0,8
Study well
1.
2|x-6|+7x-2=|x-6|+7x
2|x-6| - |x-6|=7x-(7x-2)
|x-6| = 2
=>x-6 = +2
*x-6=2 *x-6 = -2
x =2+6 x = (-2)+6
x =8 x = 4
2.
|x-5|-7(x+4)=5-7x
|x-5|-7x-28 =5-7x
|x-5|-28 =5-7x+7x
|x-5|-28 = 5
|x-5| = 5+28
|x-5| = 33
=>x-5 = +33
*x-5=33 *x-5=-33
x =38 x = -28
3.
3|x+4|-2(x-1)=7-2x
3|x+4|-2x+2 =7-2x
3|x+4|-2 =7-2x+2x
3|x+4|-2 =7
3|x+4| =7+2
3|x+4| = 9
|x+4| =9:3
|x+4| = 3
=>x+4 = +3
*x+4=3 *x+4=-3
x =-1 x = -7
a, 441 + (218 - x) = 635
<=> 441 + 218 - x = 635
<=> 659 - x = 635
=> x = 24
b, 195 - 3(x + 1) = 45
<=> 195 - 3x - 3 = 45
<=> -3x = 45 -195 + 3
<=> -3x = -147
=> x = 49
c, x - 37 - (110) = 0
<=> x - 37 -110 = 0
<=> x = 110 + 37
=> x = 147
d, (x - 36) : 15 = 15
<=> x - 36 = 15 x 15
<=> x - 36 = 225
<=> x = 225 + 36
=> x = 261
e, 2x = 32
=> x = 5
f, x50 = x
=> x = 1
Bài làm
a, 441 + ( 218 - x ) = 635
=> 441 + 218 - x = 635
=> 659 - x = 635
=> x = 659 - 635
=> x = 24
Vậy x = 24
b,195 - 3( x + 1 ) = 45
=> 195 - 3x - 3 = 45
=> 3x - 3 = 195 - 45
=> 3x - 3 = 150
=> 3x = 153
=> x = 51
Vậy x = 51
c, ( x - 37 ) - 110 = 0
=> x - 37 = 110
=> x = 110 + 37
=> x = 147
Vậy x = 147
d, ( x - 36 ) : 15 = 15
=> x - 36 = 225
=> x = 225 + 36
=> x = 261
Vậy x = 261
e, 2x = 32
Ta có: 32 = 25
=> 2x = 25
=> x = 5
Vậy x = 5
f, x50 = x
<=> x = 1 hoặc x = 0
Vậy x = 1 hoặc x = 0
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