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1.\(\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{8\times3}{33\times4}=\dfrac{8\times12}{11\times12}+\dfrac{8\times3}{33\times4}=\dfrac{8\times15}{132}=\dfrac{120}{132}=\dfrac{10}{11}\)
2.\(\dfrac{7}{9}\times\dfrac{3}{14}:\dfrac{5}{8}=\dfrac{7}{9}\times\dfrac{3}{14}\times\dfrac{8}{5}=\dfrac{4}{15}\)
3.\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}=\dfrac{5}{12}-\dfrac{7}{32}\times\dfrac{16}{21}=\dfrac{5}{12}-\dfrac{1}{6}=\dfrac{5-2}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)
`@V.Tr.V`
a, \(\frac{7}{5}+\frac{9}{7}+\frac{6}{5}+\frac{11}{7}\)
C1: \(\frac{94}{35}+\frac{6}{5}+\frac{11}{7}=\frac{136}{35}+\frac{11}{7}=5\frac{16}{35}\)
C2: \(=\left(\frac{7}{5}+\frac{6}{5}\right)+\left(\frac{9}{7}+\frac{11}{7}\right)=\frac{13}{5}+\frac{20}{7}=5\frac{16}{35}\)
b,
C1 : \(\frac{8}{14}+\frac{2}{11}+\frac{12}{14}+\frac{31}{11}=\frac{4}{7}+\frac{2}{11}+\frac{6}{7}+\frac{31}{11}=\frac{58}{77}+\frac{6}{7}+\frac{31}{11}=\frac{124}{77}+\frac{31}{11}=4\frac{3}{7}\)
C2:
\(\frac{4}{7}+\frac{2}{11}+\frac{6}{7}+\frac{31}{11}=\left(\frac{4}{7}+\frac{6}{7}\right)+\left(\frac{2}{11}+\frac{31}{11}\right)=\frac{10}{7}+3=3\frac{10}{7}=4\frac{3}{7}\)
**** cko t nha , xin xin đó
\((\)125-120\()\)x45
5x45=225
\(\dfrac{30x25x7x8}{75x8x12x14}\)=\(\dfrac{10\cdot1\cdot7\cdot1}{1\cdot1\cdot1\cdot12\cdot2}\)=\(\dfrac{70}{24}\)
\(\dfrac{11}{12}x\dfrac{6}{9}-\dfrac{3}{8}=\dfrac{66}{108}-\dfrac{3}{8}=\dfrac{17}{72}\)
\(\dfrac{5}{7}:\dfrac{9}{14}-\dfrac{17}{18}=\dfrac{70}{63}-\dfrac{17}{18}=\dfrac{1}{6}\)
\(\dfrac{11}{12}\) x \(\dfrac{6}{9}-\dfrac{3}{8}=\dfrac{11}{18}-\dfrac{3}{8}=\dfrac{88}{144}-\dfrac{54}{144}=\dfrac{34}{144}=\dfrac{17}{72}\)
\(\dfrac{5}{7}:\dfrac{9}{14}-\dfrac{17}{18}\)\(=\dfrac{5}{7}\) x \(\dfrac{14}{9}-\dfrac{17}{18}=\dfrac{10}{9}-\dfrac{17}{18}=\dfrac{20}{18}-\dfrac{17}{18}=\dfrac{3}{18}=\dfrac{1}{6}\)
1:tính
\(\frac{5}{8}\)x\(\frac{9}{7}\)+\(\frac{5}{8}\)x\(\frac{5}{7}\)
=\(\frac{5}{8}\)x\((\)\(\frac{9}{7}\)+\(\frac{5}{7}\)\()\)
=\(\frac{5}{8}\)x2
=\(\frac{5}{4}\)
# hok tốt #
\(\dfrac{14}{8}:\dfrac{7}{12}-\dfrac{3}{8}:\dfrac{9}{5}\\ =\dfrac{7}{4}:\dfrac{7}{12}-\dfrac{3}{8}:\dfrac{9}{5}\\ =\dfrac{7}{4}\times\dfrac{12}{7}-\dfrac{3}{8}\times\dfrac{5}{9}\\ =\dfrac{12}{4}-\dfrac{1\times5}{8\times3}\\ =3-\dfrac{5}{24}\\ =\dfrac{3\times24-5}{24}\\ =\dfrac{72-5}{24}\\ =\dfrac{67}{24}\)