(2x-1) tất cả mũ 4 = 16 cho mình cách giải chi tiết
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`a, 3/4 - 5/4 :(x-1) =1/2`
`=> 5/4:(x-1)= 3/4 -1/2`
`=> 5/4:(x-1)= 3/4 - 2/4`
`=> 5/4:(x-1)= 1/4`
`=> x-1= 5/4 : 1/4`
`=> x-1=5`
`=>x=5+1`
`=>x=6`
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`(1/2-x)^2 -2^2 =12`
`=> (1/2-x)^2 = 12+4`
`=> (1/2-x)^2= 16`
`=> (1/2-x)^2 =4^2`
\(\Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}-x=4\\\dfrac{1}{2}-x=-4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{7}{2}\\x=\dfrac{9}{2}\end{matrix}\right.\)
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`(1/2)^(2x-1) =1/16`
`=> (1/2)^(2x-1) = (1/2)^4`
`=> 2x-1=4`
`=> 2x=4+1`
`=>2x=5`
`=>x=5/2`
\(a,\dfrac{3}{4}-\dfrac{5}{4}:\left(x-1\right)=\dfrac{1}{2}\)
\(\dfrac{5}{4}:\left(x-1\right)=\dfrac{3}{4}-\dfrac{1}{2}\)
\(\dfrac{5}{4}:\left(x-1\right)=\dfrac{1}{4}\)
\(x-1=\dfrac{5}{4}:\dfrac{1}{4}\)
\(x-1=5\)
\(x=6\)
\(\left(\dfrac{1}{2}-x\right)^2-2^2=12\)
\(\left(\dfrac{1}{2}-x\right)^2-4=12\)
\(\left(\dfrac{1}{2}-x\right)^2=16\)
\(\left(\dfrac{1}{2}-x\right)^2=4^2hoặc\left(\dfrac{1}{2}-x\right)^2=\left(-4\right)^2\)
\(\dfrac{1}{2}-x=4hoặc\dfrac{1}{2}-x=-4\)
=>1/2 -x =4 1/2 -x= -4
=> x=1/2-4 x=1/2-(-4)
=>x=-7/2 x=9/2
vậy x∈{-7/2 ; 9/2}
\(\left(\dfrac{1}{2}\right)^{2x-1}=\dfrac{1}{16}\)
\(=>\left(\dfrac{1}{2}\right)^{2x-1}=\left(\dfrac{1}{2}\right)^4\)
\(=>2x-1=4\)
\(=>2x=5\)
\(=>x=\dfrac{5}{2}\)
\(\left(2x-1\right)^4=16=\left(\pm2\right)^4\\ =>\left[{}\begin{matrix}2x-1=2\\2x-1=-2\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)
\(\left(2x+1\right)^3=125=5^3\\ =>2x+1=1\\ =>x=2\)
1,
a/ n2 + 12n vay n co the = 2;3;5;7;11;...
=> nhung so nguyen to co 1 chu so vay n=2;3;5;7
b/ 3n + 6 vay n co the = 2;3;5;7;11;....
=> nhung so nguyen to + vao sao cho 6 ko qua 1 chu so vay n=2;3
Ta có:
VP= 3-2√3 + 1(vì 3 + 1 =4)
=√3^2 - 2√3 + √1^2
= (√3 - √1)^2
Vì \(\left|2x-6\right|\ge0\forall x;\left|2x-6\right|-4\ge-4\)
\(\Rightarrow\frac{1}{\left|2x-6\right|-4}\le\frac{1}{-4}\Rightarrow\frac{2019}{\left|2x-6\right|-4}\ge\frac{2019}{-4}\Rightarrow A\ge\frac{2019}{-4}\)
Dấu ''='' xảy ra <=> x = 3
Vậy GTNN A là -2019/4 <=> x = 3
1. \(2^x-26=6\)
\(\Rightarrow2^x=6+26\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
2. \(64\cdot4^x=16^8\)
\(\Rightarrow4^3\cdot4^x=4^{16}\)
\(\Rightarrow4^x=4^{16}:4^3\)
\(\Rightarrow4^x=4^{13}\)
\(\Rightarrow x=13\)
3. \(\left(2x-1\right)^4=16\)
\(\Rightarrow\left(2x-1\right)^4=2^4\)
\(\Rightarrow2x-1=2\)
\(\Rightarrow2x=3\)
\(\Rightarrow x=\dfrac{3}{2}\)
4. \(\left(2x+1\right)^3=125\)
\(\Rightarrow\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
(2x-1)4=16
=> (2x-1)4=24
=> 2x-1=2
=> 2x=3
=> x = \(\dfrac{3}{2}\)
( 2x -1)^4 = 16
(2x -1) ^4 = 2^4
=> 2x -1 = 2
=> 2x=2 + 1
=> 2x = 3
=> x= 1,5
Mik ko chắc là làm đúng nha !