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29 tháng 9 2018

\(d, x^3+4x^2-29x+24\)

\(=x^3+8x^2-4x^2-32x+3x+24\)

\(=x^2\left(x+8\right)-4x\left(x+8\right)+3\left(x+8\right)\)

\(=\left(x+8\right)\left(x^2-4x+3\right)\)

\(=\left(x+8\right)\left(x^2-x-3x+3\right)\)

\(=\left(x+8\right)\left[x\left(x-1\right)-3\left(x-1\right)\right]\)

\(=\left(x+8\right)\left(x-1\right)\left(x-3\right)\)

\(e, x^3+6x^2+11x+6\)

\(=x^3+3x^2+3x^2+9x+2x+3\)

\(=x^2\left(x+3\right)+3x\left(x+3\right)+2\left(x+3\right)\)

\(=\left(x+3\right)\left(x^2+3x+2\right)\)

\(=\left(x+3\right)\left(x^2+x+2x+2\right)\)

\(=\left(x+3\right)\left[x\left(x+1\right)+2\left(x+1\right)\right]\)

\(=\left(x+3\right)\left(x+1\right)\left(x+2\right)\)

29 tháng 9 2018

Mik ko giỏi p/t bậc 3 cho lắm nên có sai thì mong bạn sửa giúp :

d ) \(x^3+4x^2-29x+24\)

\(=x^2\left(x-1\right)+5x^2-10x+5-19x+19\)

\(=x^2\left(x-1\right)+5\left(x-1\right)^2-19\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+5x-5-19\right)\)

\(=\left(x-1\right)\left(x^2+5x-14\right)\)

\(=\left(x-1\right)\left(x^2+7x-2x-14\right)\)

\(=\left(x-1\right)\left(x+7\right)\left(x-2\right)\)

e ) \(x^3+6x^2+11x+6\)

\(=x^2\left(x+1\right)+5x^2+10x+5+x+1\)

\(=x^2\left(x+1\right)+5\left(x+1\right)^2+x+1\)

\(=\left(x+1\right)\left(x^2+5x+5+1\right)\)

\(=\left(x+1\right)\left(x^2+5x+6\right)\)

29 tháng 9 2018

a,   \(x^3+4x^2-29x+24\)

\(=x^3-x^2+5x^2-5x-24x+24\)

\(=x^2\left(x-1\right)+5x\left(x-1\right)-24\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+5x-24\right)\)

\(=\left(x-1\right)\left[x\left(x-3\right)+8\left(x-3\right)\right]\)

\(=\left(x-1\right)\left(x-3\right)\left(x+8\right)\)

      \(x^3+6x^2+11x+6\)

\(=x^3+x^2+5x^2+5x+6x+6\)

\(=x^2\left(x+1\right)+5x\left(x+1\right)+6\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2+5x+6\right)\)

\(=\left(x+1\right)\left[x\left(x+2\right)+3\left(x+2\right)\right]\)

\(=\left(x+1\right)\left(x+2\right)\left(x+3\right)\)

Chúc bạn học tốt.

1 tháng 10 2021

\((x-1)(x-3)(x+8)\)

 

1 tháng 10 2021

\(x^3+4x^2-29x+24\)

\(=x^2\left(x+8\right)-4x\left(x+8\right)+3\left(x+8\right)\)

\(=\left(x+8\right)\left(x^2-4x+3\right)\)

\(=\left(x+8\right)\left[x\left(x-1\right)-3\left(x-1\right)\right]\)

\(=\left(x+8\right)\left(x-1\right)\left(x-3\right)\)

13 tháng 11 2016

a) nhận xét hệ số : 1 + 4 - 29 + 24 = 0

=> x3 + 4x2 - 29x + 24 = x2(x-1) + 5x(x-1) - 24(x-1)

= (x-1)(x2+5x-24) = (x-1)(x-3)(x+8)

b) ...

13 tháng 11 2016

a) \(x^3+4x^2-29x+24\)=\(\left(x+8\right)\left(x^2-4x+3\right)\)=\(\left(x+8\right)\left(x^2-x-3x+3\right)\)=\(\left(x+8\right)\left(x-1\right)\left(x-3\right)\)

b) \(x^4+6x^3+7x^2-6x+1\)=\(x^4+3x^3-x^2+3x^3+9x^2-3x-x^2-3x+1\)=\(x^2\left(x^2+3x-1\right)+3x\left(x^2+3x-1\right)-\left(x^2+3x-1\right)\)=\(\left(x^2+3x-1\right)\left(x^2+3x-1\right)\)=\(\left(x^2+3x-1\right)^2\)

13 tháng 9 2017

a,\(=x^3-x^2+5x^2-5x-24x+24\)

\(=x^2\left(x-1\right)+5x\left(x-1\right)-24\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+5x-24\right)\)

\(=\left(x-1\right)\left(x^2-3x+8x-24\right)\)

\(=\left(x-1\right)\left(x\left(x-3\right)+8\left(x-3\right)\right)\)

\(=\left(x-1\right)\left(x-3\right)\left(x+8\right)\)

13 tháng 9 2017

a)=(x-3)(x-1)(x+8)

b)=(x2+3x-1)2

7 tháng 10 2017

a x2 - 7x - 6 = x2 -6x-x-6

= x(x-6)+(x-6)

= (x+1)(x+6)

b x3 + 4x2 - 7x -10

=x3 - 2x2 + 6x-12x+5x-10

= x2(x-2) + 6x(x-2) + 5(x-2)

= (x2 +6x+5)(x-2)

=(x2 +x+5x+5)(x-2)

=[x(x+1)+5(x+1)](x-2)

=(x+5)(x+1)(x-2)

c x3 +x2-2

=x3-x2+2x2-2x+2x-2

=x2(x-1)+2x(x-1)+2(x-1)

=(x2+2x+2)(x-1)

d x2 +5x+6

=x2 +2x+3x+6

=x(x+2)+3(x+2)

=(x+3)(x-2)

Con 1 y e nhung luoi lam

3 tháng 9 2018

mk chỉnh lại đề

\(x^2-7x+6\)

\(=x^2-x-6x+6\)

\(=x\left(x-1\right)-6\left(x-1\right)\)

\(=\left(x-1\right)\left(x-6\right)\)