Question

[Liên Bee]

Các anh chị giúp em vs ạ. E cảm ơn trước 😊

Answer 1

[Mới vô]

\(A=\dfrac{1}{1\cdot3}+\dfrac{1}{3\cdot5}+\dfrac{1}{5\cdot7}+...+\dfrac{1}{2011\cdot2013}\\ =\dfrac{1}{2}\cdot\left(\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+\dfrac{2}{5\cdot7}+...+\dfrac{2}{2011\cdot2013}\right)\\ =\dfrac{1}{2}\cdot\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{2011}-\dfrac{1}{2013}\right)\\ =\dfrac{1}{2}\cdot\left(1-\dfrac{1}{2013}\right)\\ =\dfrac{1}{2}\cdot\dfrac{2012}{2013}\\ =\dfrac{1006}{2013}\)

Answer 2

[Sáng]

Lời giải:

\(A=\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{2011.2013}\)

\(\Rightarrow A=\dfrac{2.1}{2.1.3}+\dfrac{2.1}{2.3.5}+\dfrac{2.1}{2.5.7}+...+\dfrac{2.1}{2.2011.2013}\)

\(\Rightarrow A=\dfrac{1}{2}\left(\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{2011.2013}\right)\)

\(\Rightarrow A=\dfrac{1}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{2011}-\dfrac{1}{2013}\right)\)

\(\Rightarrow A=\dfrac{1}{2}\left(1-\dfrac{1}{2013}\right)\)

\(\Rightarrow A=\dfrac{1}{2}.\dfrac{2012}{2013}\)

\(\Rightarrow A=\dfrac{1006}{2013}\)