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đây nhé!!
1+2-3-4+5+6-7-8+9+10-........+2010-2011-2012+2013+2014-2015-2016+2017
=1+(2-3-4+5)+(6-7-8+9)+(10-11-12+13)+....+(2010-2011-2012+2013)+(2014-2015-2016+2017)
=1+0+0+0+.....+0+0
=1.
ĐÚNG THÌ CHO MINK NHA!!^_^
\(\left(\frac{2013}{2011}+\frac{2014}{2012}+\frac{2015}{2013}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)=0\)
A=1+2-3-4+5+6-7-8+9+...-2012+2013+2014
A=1+(2-3-4+5)+(6-7-8+9)+...+(2010-2011-2012+2013)+2014
A=1+0+0+...+0+2014
A=2015
1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ... - 2012 + 2013 + 2014 ( có 2014 số, 2014 chia 4 dư 2)
= 1 + ( 2 - 3 - 4 + 5) + ( 6 - 7 - 8 + 9) + ... + ( 2010 - 2011 - 2012 + 2013) + 2014
= 1 + 0 + 0 + ... + 0 + 2014
= 2015 + 0 = 2015
\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}}{\frac{2013}{1}+\frac{2012}{2}+\frac{2011}{3}+...+\frac{1}{2013}}\)
\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}}{\left(\frac{2012}{2}+1\right)+\left(\frac{2011}{3}+1\right)+...+\left(\frac{1}{2013}+1\right)+1}\)
\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}}{\frac{2014}{2}+\frac{2014}{3}+...+\frac{2014}{2013}+\frac{2014}{2014}}\)
\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}}{2014.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}\right)}\)\
\(A=\frac{1}{2014}\)
=(0+1+2-3)+(-4+5+6-7)+(-8+9+10-11)+....+(-2010+2011+2012-2013)+2014
=0+0+0+...+0+2014=2014